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Geometry kills me. I was doing so well until I hit this...

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Geometry kills me. I was doing so well until I hit this...  [#permalink] New post 13 May 2008, 21:25
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A
B
C
D
E

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Geometry kills me. I was doing so well until I hit this...

Please note D is not the OA - rather it is my random guess after scratching my head for 5 mts.
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Re: GMATPrep1 - Geometry PS [#permalink] New post 13 May 2008, 22:12
Expert's post
A

\frac{40}{360}=\frac{x}{18\pi}

x=2\pi
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Re: GMATPrep1 - Geometry PS [#permalink] New post 13 May 2008, 22:15
How did you get the two 35 s at angle P. I know one of the 35's is because the two lines are parallel, how did u derive the other one ?

Last edited by bsd_lover on 13 May 2008, 22:15, edited 1 time in total.
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Re: GMATPrep1 - Geometry PS [#permalink] New post 13 May 2008, 22:15
the answer will be (A) 2 Pi

Explanation:

L(ARC PO)= 35/360 * 2*Pi*9
=3.5 Pi.

Angle PRO and Angle QPR are same =35 (since Line OR is ll to PQ)

L(ARC PO) = L(ARC QR)=3.5 Pi


L(ARC OPQR)= 180/360 * 2*Pi*9 (Since Arc OPQR forms a semicircle hence theta = 180)
=9 Pi.

hence
L(OPQR) = L(Arc OP)+L(Arc PQ)+L(Arc QR)
L(Arc PQ) = 9 Pi - (3.5 Pi +3.5 Pi)
= 2 Pi

Hence the Option A is correct.
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Re: GMATPrep1 - Geometry PS [#permalink] New post 13 May 2008, 22:42
bsd_lover wrote:
How did you get the two 35 s at angle P. I know one of the 35's is because the two lines are parallel, how did u derive the other one ?


If still not get the point, let me know!
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Re: GMATPrep1 - Geometry PS [#permalink] New post 13 May 2008, 22:42
Expert's post
bsd_lover wrote:
How did you get the two 35 s at angle P. I know one of the 35's is because the two lines are parallel, how did u derive the other one ?


the other angle is 35 because the triangle PR (center) is isosceles: P(center)=R(center)=radius.
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Re: GMATPrep1 - Geometry PS [#permalink] New post 14 May 2008, 00:00
Yup got it .. thanks walker !!! +1.
Re: GMATPrep1 - Geometry PS   [#permalink] 14 May 2008, 00:00
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