Geometry Problem : Quant Question Archive [LOCKED]
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# Geometry Problem

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22 Oct 2008, 16:42
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Thanks!
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22 Oct 2008, 16:48
B - 24/25

4s = 2(l+w)
l/w = 2/3
so,
s = 5/6w

Question asks for (l*w)/(s^2) = (2/3)/(25/36) = 24/25
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22 Oct 2008, 16:49
Poots: I think you are posting your questions in the wrong section
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22 Oct 2008, 17:06
Oh, you're so right, LS. I am posting them wrong. See what GMAT does to me?!
Do you know how I can move them or is all hope lost?
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22 Oct 2008, 22:40
just make the sides of the rectangle 2 and 3, the area is 6
that means that the perimeter is 10 (2+3+2+3)
the perimeter of the square is 10 also so each side is 10/4
the area of the square is 10/4*10/4=100/16=25/4
so the ratio of area of R to S is 6 / 25/4 or 24/25
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23 Oct 2008, 03:35
LiveStronger wrote:
B - 24/25

4s = 2(l+w)
l/w = 2/3
so,
s = 5/6w

Question asks for (l*w)/(s^2) = (2/3)/(25/36) = 24/25

l/w = 2/3 ---> shouldn't it be w/l = 2/3 ?? length > width ,
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23 Oct 2008, 07:47
Rectangular's sides are 2, 3, 2, 3, therefore perimeter is 10
If the square has the same perimeter - 10 - that means that the lengh of one side is 2,5
Area of rectangular is 2*3=6
Area of square 2,5*2,5=6,25
Although we do not have answer choice for that, and we need integers in ratio, therefore we multiply both areas by 4 and get 24:25
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23 Oct 2008, 09:26
amitdgr wrote:
LiveStronger wrote:
B - 24/25

4s = 2(l+w)
l/w = 2/3
so,
s = 5/6w

Question asks for (l*w)/(s^2) = (2/3)/(25/36) = 24/25

l/w = 2/3 ---> shouldn't it be w/l = 2/3 ?? length > width ,

either way will work amit. Make sure you calculate the right value for 's' though
Re: Geometry Problem   [#permalink] 23 Oct 2008, 09:26
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