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# Given a spinner with four sections of equal size labeled

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Given a spinner with four sections of equal size labeled [#permalink]

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01 May 2012, 03:28
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Given a spinner with four sections of equal size labeled A, B, C, and D, what is the probability of NOT getting an A after spinning the spinner two times?

A. 15/16
B. 9/16
C. 1/2
D. 1/4
E. 1/8
[Reveal] Spoiler: OA
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Re: Given a spinner with four sections of equal size labeled [#permalink]

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01 May 2012, 03:38
Given a spinner with four sections of equal size labeled A, B, C, and D, what is the probability of NOT getting an A after spinning the spinner two times?

A. 15/16
B. 9/16
C. 1/2
D. 1/4
E. 1/8

The probability of NOT getting an A after spinning the spinner two times is 3/4*3/4=9/16 (so getting any of the remaining 3 letters out of 4).

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Re: Given a spinner with four sections of equal size labeled [#permalink]

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01 May 2012, 10:31
Bunel, if you don't mind I want to expand on this problem for other probability concepts.

A. If I was to do 1 - (1/4*1/4) = 15/16.....This should be the right answer to what type of question?
C. 1/4 + 1/4 = 1/2, I assume this would be the right answer for "Probability of hitting A on any one of the two tries"?
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Re: Given a spinner with four sections of equal size labeled [#permalink]

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02 May 2012, 16:26
ashish8 wrote:
Bunel, if you don't mind I want to expand on this problem for other probability concepts.

A. If I was to do 1 - (1/4*1/4) = 15/16.....This should be the right answer to what type of question?
C. 1/4 + 1/4 = 1/2, I assume this would be the right answer for "Probability of hitting A on any one of the two tries"?

I am going to give it a shot, hopefully someone can confirm/correct me.
For A - that will be the right answer if the question were, what is the probablity if the hits atleast once if spun twice?
p(e) = 1 - (p(no A at all)

For B - that will be right, if the question were, what is the probality if spinner hit A on first spin or second spin?
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Re: Given a spinner with four sections of equal size labeled [#permalink]

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02 May 2012, 16:34
Jay wouldn't the probability of A at least once be, 1 - Probability of NOT A = 1 - (3/4*3/4) = 1 - 9/16 = 7/16 ?
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Re: Given a spinner with four sections of equal size labeled [#permalink]

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03 May 2012, 12:49
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Expert's post
The probability of:
Getting A at leas once after spinning the spinner two times is 1-3/4*3/4=7/16;
Getting A only once after spinning the spinner two times is 1/4*3/4+3/4*1/4=6/16;
NOT getting A on both spins (so no AA) is 1-1/4*1/4=15/16.

Hope it's clear.
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Re: Given a spinner with four sections of equal size labeled [#permalink]

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03 May 2012, 19:08
ashish8 wrote:
Bunel, if you don't mind I want to expand on this problem for other probability concepts.

A. If I was to do 1 - (1/4*1/4) = 15/16.....This should be the right answer to what type of question?
C. 1/4 + 1/4 = 1/2, I assume this would be the right answer for "Probability of hitting A on any one of the two tries"?

it should be (1 - 1/4) * (1 - 1/4),
not 1 - (1/4*1/4)

this is because both need to happen simultaneousluy, so we need to multiply. if both can happen idepedently, we can add.
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Re: Given a spinner with four sections of equal size labeled [#permalink]

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04 May 2012, 20:55
ashish8 wrote:
C. 1/4 + 1/4 = 1/2, I assume this would be the right answer for "Probability of hitting A on any one of the two tries"?

The right answer is (1/4) + (1/4) - (1/4)*(1/4) = 7/16
and the right question is: What is the probability that you get A at least once? or What is the probability of getting A on any one of the two tries or on both?

You subtract the probability of getting A on both spins because you have double counted it. Think SETS. The first (1/4) includes the probability of 'A on both spins'. The second (1/4) also includes the probability of 'A on both spins'. So you need to subtract it once.
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews GMAT Club Legend Joined: 09 Sep 2013 Posts: 12262 Followers: 542 Kudos [?]: 151 [0], given: 0 Re: Given a spinner with four sections of equal size labeled [#permalink] ### Show Tags 01 Dec 2013, 06:28 Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________ Current Student Status: Everyone is a leader. Just stop listening to others. Joined: 22 Mar 2013 Posts: 993 Location: India GPA: 3.51 WE: Information Technology (Computer Software) Followers: 163 Kudos [?]: 1370 [0], given: 226 Re: Given a spinner with four sections of equal size labeled [#permalink] ### Show Tags 17 May 2014, 13:07 Meaning is confusing ... after spinning 2 times .. means third time or more.. or spinning spinner by hand 2 times.. _________________ Piyush K ----------------------- Our greatest weakness lies in giving up. The most certain way to succeed is to try just one more time. ― Thomas A. Edison Don't forget to press--> Kudos My Articles: 1. WOULD: when to use? | 2. All GMATPrep RCs (New) Tip: Before exam a week earlier don't forget to exhaust all gmatprep problems specially for "sentence correction". Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 6972 Location: Pune, India Followers: 2034 Kudos [?]: 12790 [0], given: 221 Re: Given a spinner with four sections of equal size labeled [#permalink] ### Show Tags 18 May 2014, 21:36 PiyushK wrote: Meaning is confusing ... after spinning 2 times .. means third time or more.. or spinning spinner by hand 2 times.. "Not getting A after spinning 2 times" means not getting A in either of the two spins. _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: Given a spinner with four sections of equal size labeled [#permalink]

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24 Oct 2016, 20:22
Bunuel wrote:
The probability of:
Getting A at leas once after spinning the spinner two times is 1-3/4*3/4=7/16;
Getting A only once after spinning the spinner two times is 1/4*3/4+3/4*1/4=6/16;
NOT getting A on both spins (so no AA) is 1-1/4*1/4=15/16.

Hope it's clear.

Hey Bunuel,

what is the difference between "NOT getting an A after spinning the spinner two times" and "NOT getting A on both spins"?
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Re: Given a spinner with four sections of equal size labeled   [#permalink] 24 Oct 2016, 20:22
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