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# Given a triangle with sides 5 and 13. What is the length of

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Intern
Joined: 13 May 2009
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Given a triangle with sides 5 and 13. What is the length of [#permalink]  08 Aug 2009, 09:01
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Given a triangle with sides 5 and 13.
What is the length of segment BC?
(1) Angle ABC is 90 degrees.
(2) The area of the triangle is 30.
Director
Joined: 01 Apr 2008
Posts: 906
Schools: IIM Lucknow (IPMX) - Class of 2014
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Kudos [?]: 305 [0], given: 18

Re: Given a triangle with sides 5 and 13. [#permalink]  08 Aug 2009, 09:09
E for me.

1) Since one angle is 90 degrees and two of the sides are 5 and 13 the third side will definitely be 12. This will be one of the legs, i.e. AB or BC. Hence, BC can be 5 or 12.
INSUFF.

2) Area is 30. Again we have the same problem.
INSUFF
Combining also we cannot say for sure which leg is the base and which is the altitude.
Manager
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Re: Given a triangle with sides 5 and 13. [#permalink]  08 Aug 2009, 09:14
Is it mentioned in the question that AB & CA are 5 & 13? Or is it given as 5 and 13 are two sides of the triangle. Based on these only we can arrive at the solution. Please post the exact question.
Manager
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Re: Given a triangle with sides 5 and 13. [#permalink]  08 Aug 2009, 14:43
If figure is not given, I would like to go with E.

What is the OA?
Senior Manager
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Re: Given a triangle with sides 5 and 13. [#permalink]  08 Aug 2009, 20:20
lbsgmat wrote:
Given a triangle with sides 5 and 13.
What is the length of segment BC?
(1) Angle ABC is 90 degrees.
(2) The area of the triangle is 30.

I don't get the bold part?
Intern
Joined: 10 Jul 2009
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Re: Given a triangle with sides 5 and 13. [#permalink]  09 Aug 2009, 04:03
1
KUDOS

St 1. We are told that one of the angles is 90 but we don't know which. We know for sure that the side that equals 5 cannot be hypothenuse. Thus, the side 13 can be either the second leg of the right triangle or the hypothenuse. INSF

St2 Gives us an area (30) but we can not derive anything from that

If you combine 2 Stms we are able to identify whether 13 is a leg or hypothenus.

Area=1/2 * H * Base

we know that 5 is a base (or can be a hight) let's try to plug in numbers:

1/2 * 5 * 13 = 32,5 , since we are told that the area=30. Side 13 can not be a leg, thus - hypothenuse.
we can say with confidence that the third side = 12 (1/2*5*12=30)
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Re: Given a triangle with sides 5 and 13. [#permalink]  10 Aug 2009, 00:23
I would say the question lacks clarity ...
Dunno if this is the exact question or not....

if not then plz post the exact query ...
the first sentence does not even mention that the Triangle is ABC ....what if it is PQR????

it says about the triangle and then jumps straight to the question asking for the length of line segment BC...

wat is BC ?
Re: Given a triangle with sides 5 and 13.   [#permalink] 10 Aug 2009, 00:23
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