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Re: Given that 6 is a divisor of rand r is a factor of 5, is 6 a [#permalink]
20 Aug 2011, 00:43
How to solve this ? Please explain in detail
Given that 6 is a divisor of rand r is a factor of 5, is 6 a factor of 5?
This question is either stupid or there is a typo.
The red text becomes irrelevant if we just need to answer whether 6 a factor of 5. The answer to that is NO. 6 is Not a factor of 5; 1 and 5 are factors of 5, as jamifahad already said.
siddhans: Please check the question again.
My bad, the question should be : Given that 6 is a divisor of r and r is a factor of s, is 6 a factor of s?
Here is my comment -
If 6 is a divisor or r, then r must be a multiple of 6. Do you get this part? Say r = 12, 12 is divisible by 6 and thus is a multiple of 6. If r is further a factor of s, that means s is a multiple of r.
All this means is that if you add 'few' (exact number doesnt matter) 6's, you get r and if you add 'few' (again number not important) r's, you get s. And because s is made up of r's and r's in turn are made up of 6's, s must be made of 6's as well. Do you understand all this? So yes, 6 must be a factor of s.
IMPORTANT NOTE:- If 6 is a divisor of r, that means r/6 = integer. You could say that if r = zero, r/6 = zero (integer)(Also zero is a multiple of anything). This means r is made up of 'zero' number of 6's. Its all ok till this part. But r cannot be zero in this question particularly, because if we go further in the question, r is a factor of s. ZERO CANNOT BE A FACTOR OF ANYTHING BECAUSE ANYTHING/ZERO = NOT DEFINED.