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Given that p is a positive even integer with a positive [#permalink]
08 Aug 2006, 12:59
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A
B
C
D
E
Difficulty:
75% (hard)
Question Stats:
53% (02:06) correct
47% (01:10) wrong based on 242 sessions
Given that p is a positive even integer with a positive units digit, if the units digit of p^3 minus the units digit of p^2 is equal to 0, what is the units digit of p + 3?
A. 3 B. 6 C. 7 D. 9 E. It cannot be determined from the given information.
Unit digit of p^3 = unit digit of x^3
Unit digit of p^2 = unit digit of x^2
Their difference is 0 (As given). This is possible only if unit digit is 1 or 0. But since p is an even integer. So unit digit of p =0
hence unit digit of p+3 = 3 _________________
Unit digit of p^3 = unit digit of x^3 Unit digit of p^2 = unit digit of x^2
Their difference is 0 (As given). This is possible only if unit digit is 1 or 0. But since p is an even integer. So unit digit of p =0 hence unit digit of p+3 = 3
What the heck I was thinking
Answer should be D because last digit of p must be +ve and even. _________________
Re: PS: Digits again [#permalink]
08 Aug 2006, 13:42
u2lover wrote:
Given that p is a positive even integer with a positive units digit, if the units digit of p^3 minus the units digit of p^2 is equal to 0, what is the units digit of p + 3?
A 3 B 6 C 7 D 9 E It cannot be determined from the given information.
please explain
unit digits could be 0, 1, 5 and 6 but only 6 satisfies the conditions given in the question. so D make sense..
Re: PS: Digits again [#permalink]
09 Aug 2006, 16:13
u2lover wrote:
Given that p is a positive even integer with a positive units digit, if the units digit of p^3 minus the units digit of p^2 is equal to 0, what is the units digit of p + 3?
A 3 B 6 C 7 D 9 E It cannot be determined from the given information.
please explain
If units digit = 6 then units(216)-units(36) = 0
p+3 = 9
Re: Given that p is a positive even integer with a positive [#permalink]
28 Sep 2013, 11:31
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Re: Given that p is a positive even integer with a positive [#permalink]
29 Sep 2013, 08:57
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u2lover wrote:
Given that p is a positive even integer with a positive units digit, if the units digit of p^3 minus the units digit of p^2 is equal to 0, what is the units digit of p + 3?
A. 3 B. 6 C. 7 D. 9 E. It cannot be determined from the given information.
p is a positive even integer with a positive units digit --> the units digit of p can be 2, 4, 6, or 8 --> only options C and E are left.
In order the units digit of p^3 - p^2 to be 0, the units digit of p^3 and p^2 must be the same. Thus the units digit of p can be 0, 1, 5 or 6.
Intersection of values is 6, thus the units digit of p + 3 is 6 + 3 = 9.
Re: Given that p is a positive even integer with a positive [#permalink]
03 Oct 2015, 19:59
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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