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Given the ascending set of positive integers {a, b, c, d, e, [#permalink]
 19 Jun 2011, 14:36
Question Stats:
60% (02:03) correct
40% (01:13) wrong based on 40 sessions
Given the ascending set of positive integers {a, b, c, d, e, f}, is the median greater than the mean? (1) a + e = (3/4)(c + d) (2) b + f = (4/3)(c + d)
Last edited by siddhans on 20 Jun 2011, 22:32, edited 1 time in total.
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bong1993 wrote: C it is Please give detailed steps...Dont just give A,B, c...I already know its C
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Re: Given the ascending set of positive integers {a, b, c, d, e, [#permalink]
04 Aug 2012, 15:59
Anyone can provide the logic behind this please..
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Re: Given the ascending set of positive integers {a, b, c, d, e, [#permalink]
04 Aug 2012, 16:00
Bunuel If you can provide your inputs pls that vvill help
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Re: Given the ascending set of positive integers {a, b, c, d, e, [#permalink]
04 Aug 2012, 16:32
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Given the ascending set of positive integers {a, b, c, d, e, f}, is the median greater than the mean?The median of a set with even number of elements is the average of two middle elements when arranged in ascending/descending order. Thus, the median of {a, b, c, d, e, f} is \frac{c+d}{2}. So, the question asks: is \frac{c+d}{2}>\frac{a+b+c+d+e+f}{6}? --> is 3c+3d>a+b+c+d+e+f? --> is 2(c+d)>a+b+e+f? (1) a + e = (3/4)(c + d) --> the question becomes: is 2(c+d)>b+f+\frac{3}{4}(c + d)? --> is \frac{5}{4}(c + d)>b+f? Not sufficient. (2) b + f = (4/3)(c + d). The same way as above you can derive that this statement is not sufficient. (1)+(2) The question in (1) became: is \frac{5}{4}(c + d)>b+f? Since (2) says that b + f = \frac{4}{3}(c + d), then the question becomes: is \frac{5}{4}(c + d)>\frac{4}{3}(c + d)? --> is \frac{1}{12}(c+d)<0? --> is c+d<0? As given that c and d are positive numbers, then the answer to this question is definite NO. Sufficient. Answer: C. Not a good question.
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Re: Given the ascending set of positive integers {a, b, c, d, e, [#permalink]
04 Aug 2012, 18:37
Bunuel Is this not a GMAT type question ? Bunuel wrote: Given the ascending set of positive integers {a, b, c, d, e, f}, is the median greater than the mean?
The median of a set with even number of elements is the average of two middle elements when arranged in ascending/descending order. Thus, the median of {a, b, c, d, e, f} is \frac{c+d}{2}.
So, the question asks: is \frac{c+d}{2}>\frac{a+b+c+d+e+f}{6}? --> is 3c+3d>a+b+c+d+e+f? --> is 2(c+d)>a+b+e+f?
(1) a + e = (3/4)(c + d) --> the question becomes: is 2(c+d)>b+f+\frac{3}{4}(c + d)? --> is \frac{5}{4}(c + d)>b+f? Not sufficient.
(2) b + f = (4/3)(c + d). The same way as above you can derive that this statement is not sufficient.
(1)+(2) The question in (1) became: is \frac{5}{4}(c + d)>b+f? Since (2) says that b + f = \frac{4}{3}(c + d), then the question becomes: is \frac{5}{4}(c + d)>\frac{4}{3}(c + d)? --> is \frac{1}{12}(c+d)<0? --> is c+d<0? As given that c and d are positive numbers, then the answer to this question is definite NO. Sufficient.
Answer: C.
Not a good question.
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Re: Given the ascending set of positive integers {a, b, c, d, e, [#permalink]
04 Aug 2012, 18:40
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Re: Given the ascending set of positive integers {a, b, c, d, e, [#permalink]
12 Feb 2013, 14:29
if all of the integers are positive, then how come c+d<o ?
question system contradicts with the solution...
You are right Bunuel.. not an air tight question.
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Re: Given the ascending set of positive integers {a, b, c, d, e, [#permalink]
13 Feb 2013, 01:17
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Re: Given the ascending set of positive integers {a, b, c, d, e,
[#permalink]
13 Feb 2013, 01:17
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