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Re: Given the sequence above, what is the sum of the 10th and the 20th [#permalink]
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Expert Reply
Bunuel wrote:
8, 19, 30, 41, 52, ….
Given the sequence above, what is the sum of the 10th and the 20th terms?

A. 324
B. 335
C. 346
D. 357
E. 368


Kudos for a correct solution.


This is an Arithmatic progression with First term 8 and Common Difference = 19-8 = 30-19 = 11

10th Term = First term + 9*Common Difference = 8+9*11 = 107

20th Term = First term + 19*Common Difference = 8+19*11 = 217

Difference = 217 + 107 = 324

Answer: option A
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Re: Given the sequence above, what is the sum of the 10th and the 20th [#permalink]
1
Kudos
Bunuel wrote:
8, 19, 30, 41, 52, ….
Given the sequence above, what is the sum of the 10th and the 20th terms?

A. 324
B. 335
C. 346
D. 357
E. 368


Kudos for a correct solution.



The terms are in A.P
a=8, d=11
a10=a+9d=8+9(11)=107
And, a20=a+19d=9+19(11)=217
Therefore, a10+a20=107+217=324
Answer A
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Given the sequence above, what is the sum of the 10th and the 20th [#permalink]
1
Kudos
Bunuel wrote:
8, 19, 30, 41, 52, ….
Given the sequence above, what is the sum of the 10th and the 20th terms?

A. 324
B. 335
C. 346
D. 357
E. 368


Kudos for a correct solution.


First term a =8
Difference btw two consecutive terms = 11

Formula to calculate nth term when the seq is A.P is = a + (n-1)* d

10th term = 8 + (10-1) * 11 = 107
20th term = 8 + (20-1) * 11 = 217

Sum = 107+217 = 324

Option A
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Re: Given the sequence above, what is the sum of the 10th and the 20th [#permalink]
1
Kudos
The series has numbers spaced out by 11. So the equation can be written as 8+ 11(n-1).

The 10th number will be - 8+11(9) = 107
20th number - 8+11(19) = 217

Sum is 324, hence answer is A


Bunuel wrote:
8, 19, 30, 41, 52, ….
Given the sequence above, what is the sum of the 10th and the 20th terms?

A. 324
B. 335
C. 346
D. 357
E. 368


Kudos for a correct solution.
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Re: Given the sequence above, what is the sum of the 10th and the 20th [#permalink]
1
Kudos
This is a case of AP with following :
first term=8, difference=11.

To find the 10th term, use the following formula:
nth term==a+(n-1)*d, where a==first term, n==number of terms, d==difference

10th term = 8 + (10-1) * 11 ==107
20th term = 8 + (20-1) * 11 ==217

Sum of 10th and 20th term = 107 + 217 == 324. A is correct answer

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Re: Given the sequence above, what is the sum of the 10th and the 20th [#permalink]
1
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Expert Reply
Bunuel wrote:
8, 19, 30, 41, 52, ….
Given the sequence above, what is the sum of the 10th and the 20th terms?

A. 324
B. 335
C. 346
D. 357
E. 368


Kudos for a correct solution.


800score Official Solution:

First, we need to derive a formula so that we do not need to write out the first 20 terms.
The first term is 8 = 11 – 3. The second term is 19 = 22 – 3, the third term is 30 = 3 × 11 – 3, the fourth term is 41 = 4 × 11 – 3, etc.
Thus, 11n – 3 describes the values in the sequence where n is the number of the term.
The 10th term is 10 × 11 – 3 = 107.
The 20th term is 20 × 11 – 3 = 220 – 3 = 217.
The sum of these two values is 324.

The correct answer is choice (A).
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Re: Given the sequence above, what is the sum of the 10th and the 20th [#permalink]
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Re: Given the sequence above, what is the sum of the 10th and the 20th [#permalink]
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