hgp2k wrote:

srini123 wrote:

3^3=27

and 3^3^3 = 3^27

where is the doubt ?

srini123

I can understand if the question is: 3^(3^3). In this case we have to solve the bracket first. But the question does not say that. So according to basic rules of exponents, it should be 3^(3

*3) = 3^9 and not 3^27.

- also I didn't quite get where did the

* come from ? I see now,

((3^3)^3 = 3^9), but for the one in question we need to apply precedence of operators (see below)

As per precedence of power, 3^3^3 = 3^(3^3)

see

http://en.wikipedia.org/wiki/Order_of_operationsspecifically, example

2. Evaluate exponential powers; for iterated powers, start from the right:

2^{3^2}=2^{[3^2]}=[2^9]=512

_________________

Thanks, Sri

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