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# GMAT Club test M25: # 31

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GMAT Club test M25: # 31 [#permalink]

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09 Nov 2009, 20:47
Guys help me understand one thing here.

Is 3^3^3 = 3^9 or 3^27?
I think it should be 3^9 and not 3^27
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Last edited by hgp2k on 09 Nov 2009, 20:52, edited 1 time in total.
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Re: GMAT Club test M25: # 31 [#permalink]

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09 Nov 2009, 20:51
3^3=27

and 3^3^3 = 3^27

where is the doubt ?
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Re: GMAT Club test M25: # 31 [#permalink]

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09 Nov 2009, 20:53
hgp2k wrote:
Guys help me understand one thing here.

Is 3^3^3 = 3^9 or 3^27?
I think it should be 3^9 and not 3^27

It is 3^27

3^3^3 = 3^(3^3) = 3^27
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Re: GMAT Club test M25: # 31 [#permalink]

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09 Nov 2009, 20:55
srini123 wrote:
3^3=27

and 3^3^3 = 3^27

where is the doubt ?

srini123
I can understand if the question is: 3^(3^3). In this case we have to solve the bracket first. But the question does not say that. So according to basic rules of exponents, it should be 3^(3*3) = 3^9 and not 3^27.
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Re: GMAT Club test M25: # 31 [#permalink]

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09 Nov 2009, 21:00
2
KUDOS
hgp2k wrote:
srini123 wrote:
3^3=27

and 3^3^3 = 3^27

where is the doubt ?

srini123
I can understand if the question is: 3^(3^3). In this case we have to solve the bracket first. But the question does not say that. So according to basic rules of exponents, it should be 3^(3*3) = 3^9 and not 3^27.
- also I didn't quite get where did the * come from ? I see now, $$((3^3)^3 = 3^9)$$, but for the one in question we need to apply precedence of operators (see below)

As per precedence of power, 3^3^3 = 3^(3^3)

see http://en.wikipedia.org/wiki/Order_of_operations
specifically, example
2. Evaluate exponential powers; for iterated powers, start from the right:

2^{3^2}=2^{[3^2]}=[2^9]=512
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Re: GMAT Club test M25: # 31 [#permalink]

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09 Nov 2009, 21:08
okay, I got it now. Thanks Srini +1 for quick answer and all your help
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Re: GMAT Club test M25: # 31 [#permalink]

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09 Nov 2009, 23:48
This question has already been discussed:

Please don't create double posts on the same questions. You can search this thread:

Also, don't forget to use forum search and Custom Google Search for the same purpose.

Thank you .
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Re: GMAT Club test M25: # 31 [#permalink]

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10 Nov 2009, 04:10
Thanks dzyubam! I will take care of it going further.
Re: GMAT Club test M25: # 31   [#permalink] 10 Nov 2009, 04:10
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# GMAT Club test M25: # 31

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