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GMAT Diagnostic Test Question 6 [#permalink ]
06 Jun 2009, 20:39
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GMAT Diagnostic Test Question 6 Field: fractions, powers

Difficulty: 700

What is the value of

\frac{\frac{1}{8} * (\frac{1}{16})^2* 4^4}{(\frac{1}{64})^{\frac{1}{2}} * 2^{-4} ?

A. 16

B. 4

C. 2

D.

\frac{1}{2} E.

\frac{1}{16} _________________

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Last edited by

Bunuel on 06 Oct 2013, 23:06, edited 3 times in total.

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
15 Jun 2009, 07:12
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Re: GMAT Diagnostic Test Question 6 [#permalink ]
16 Sep 2009, 21:50

Do you really think this is a 750 question? It seemed easier than some of the other 700-650 questions. Just my 2 cents.

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
21 Nov 2009, 01:22

robertrdzak wrote:

Do you really think this is a 750 question? It seemed easier than some of the other 700-650 questions. Just my 2 cents.

I agree. A bit surprised by the level

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
16 Dec 2009, 08:40

Agree that the question is pretty easy:)

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
16 Dec 2009, 08:51

yep , I got it in 20 secs, is it 750 level ?

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
21 Dec 2009, 07:15

dzyubam wrote:

Explanation:

Official Answer: A We just have to simplify the expression:

\frac{\frac{1}{8} * (\frac{1}{16})^2 * 4^4}{\left(\frac{1}{64}\right)^{\frac{1}{2}} * 2^{-4}} = \frac{\frac{1}{2^3} * \frac{1}{2^8} * 2^8}{\frac{1}{8} * \frac{1}{2^4}} = \frac{\frac{1}{2^3}}{\frac{1}{2^3} * \frac{1}{2^4}} = 2^4 = 16 can someone pls xplain how 2^{-4}= 1/2^ 4?

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
21 Dec 2009, 07:32
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a^{-b} = \frac{1}{a^b} It's just an exponent property.

sunnyvee wrote:

dzyubam wrote:

Explanation:

Official Answer: A We just have to simplify the expression:

\frac{\frac{1}{8} * (\frac{1}{16})^2 * 4^4}{\left(\frac{1}{64}\right)^{\frac{1}{2}} * 2^{-4}} = \frac{\frac{1}{2^3} * \frac{1}{2^8} * 2^8}{\frac{1}{8} * \frac{1}{2^4}} = \frac{\frac{1}{2^3}}{\frac{1}{2^3} * \frac{1}{2^4}} = 2^4 = 16 can someone pls xplain how 2^{-4}= 1/2^ 4?

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
21 Dec 2009, 07:51

thanx dzyubam, heres a kudo to make it worth ur while

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
11 Jan 2010, 21:48

dzyubam wrote:

Explanation:

Official Answer: A We just have to simplify the expression:

\frac{\frac{1}{8} * (\frac{1}{16})^2 * 4^4}{\left(\frac{1}{64}\right)^{\frac{1}{2}} * 2^{-4}} = \frac{\frac{1}{2^3} * \frac{1}{2^8} * 2^8}{\frac{1}{8} * \frac{1}{2^4}} = \frac{\frac{1}{2^3}}{\frac{1}{2^3} * \frac{1}{2^4}} = 2^4 = 16 Please confirm. Correct answer is 2^4 because the two 1/2^3 cancel out and leave 1/1/2^4?

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
12 Jan 2010, 06:43

You're absolutely right

.

gottabwise wrote:

Please confirm. Correct answer is 2^4 because the two 1/2^3 cancel out and leave 1/1/2^4?

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
12 Jan 2010, 10:35

dzyubam wrote:

You're absolutely right

.

gottabwise wrote:

Please confirm. Correct answer is 2^4 because the two 1/2^3 cancel out and leave 1/1/2^4?

dzyubam: Thanks for confirming.

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
24 Jan 2010, 09:34

Thanks for the question and answer. Got it wrong for the first try.

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
02 Apr 2010, 05:11

I agree, this question shouldn't be of 750 difficulty level.

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
08 Apr 2010, 15:29

650-700 level i must say

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
23 Apr 2010, 09:21

gmatbull wrote:

I agree, this question shouldn't be of 750 difficulty level.

Well for someone, it is difficult to solve it in once.

I agree that it is of 650-700 level.

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
20 May 2010, 10:21

600-650 level! the question is straight forward and test basic knowledge. Just be careful when changing the fraction into negative exponent.

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
04 Oct 2010, 02:26

This may seem like a stupid question but could someone please explain what happend to 1/2^8 * 2^8 in the nominator from the second to third step? I tried to figure it out myself and looked up the math basics topic but haven't been successful. Thanks!

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
04 Oct 2010, 02:31

\frac{1}{2^8} and

2^8 just canceled out, just as

\frac{1}{7} and

7 would.

\frac{1}{2^8} * 2^8 = 1 HanibalSmith wrote:

This may seem like a stupid question but could someone please explain what happend to 1/2^8 * 2^8 in the nominator from the second to third step? I tried to figure it out myself and looked up the math basics topic but haven't been successful. Thanks!

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Re: GMAT Diagnostic Test Question 6 [#permalink ]
04 Oct 2010, 04:25

Ahh... Of course.... Thanks!

Re: GMAT Diagnostic Test Question 6
[#permalink ]
04 Oct 2010, 04:25