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GMAT Diagnostic Test Question 24

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Re: GMAT Diagnostic Test Question 25 [#permalink]

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03 Dec 2011, 13:05
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Re: GMAT Diagnostic Test Question 25 [#permalink]

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18 Jan 2012, 08:32
Great question, but I'd agree: There's no way this would be a 600-level-question. 700 sounds about right.
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Re: GMAT Diagnostic Test Question 25 [#permalink]

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15 Jun 2013, 19:17
I tried something else and it doesn't add up.

Expressed in minutes, on day one, the distance to P is 120*s (120mins=2 hrs, s=speed)

Then for bus 1 on the second day, distance covered is (120-24)*s =96s

So shouldn't distance to P (120*s) minus 24 miles equal 96s? As in 120s-24=96s, which would calculate to s=1mile/min=60mph
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Re: GMAT Diagnostic Test Question 25 [#permalink]

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14 Aug 2013, 15:52
Bunuel wrote:
Distance between the cities $$d$$.

First meeting point $$\frac{d}{2}$$, as both buses travel at the same constant speed and leave the cities same time they meet at the halfway.

Total time to cover the $$d$$ 4 hours, as the buses meet in 2 hours.

On the second day first bus traveled alone 1 hour (36min +24min), hence covered $$0.25d$$, and $$0.75d$$ is left cover.

They meet again at the halfway of $$0.75d$$, which is 24 miles from $$\frac{d}{2}$$:

$$\frac{d}{2}-24=\frac{0.75d}{2}$$

$$d=192$$

You destroyed that problem and took its lunch money too. So this is a great opportunity for me to ask a question about a concept that I've never fully understood. When you create this equation:

$$\frac{d}{2}-24=\frac{0.75d}{2}$$

What makes you subtract 24 instead of add 24? I feel like either one signifies "distance from", right?
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Re: GMAT Diagnostic Test Question 25 [#permalink]

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15 Aug 2013, 02:55
Expert's post
Bunuel wrote:
Distance between the cities $$d$$.

First meeting point $$\frac{d}{2}$$, as both buses travel at the same constant speed and leave the cities same time they meet at the halfway.

Total time to cover the $$d$$ 4 hours, as the buses meet in 2 hours.

On the second day first bus traveled alone 1 hour (36min +24min), hence covered $$0.25d$$, and $$0.75d$$ is left cover.

They meet again at the halfway of $$0.75d$$, which is 24 miles from $$\frac{d}{2}$$:

$$\frac{d}{2}-24=\frac{0.75d}{2}$$

$$d=192$$

You destroyed that problem and took its lunch money too. So this is a great opportunity for me to ask a question about a concept that I've never fully understood. When you create this equation:

$$\frac{d}{2}-24=\frac{0.75d}{2}$$

What makes you subtract 24 instead of add 24? I feel like either one signifies "distance from", right?

The simple fact that d/2 is greater than 0.75(d/2).

Does this make sense?
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Re: GMAT Diagnostic Test Question 24 [#permalink]

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10 Nov 2013, 10:09
Hey guys, just to let you know that I downloaded the PDF and the the problem says: "If they meet 48 miles from point P, ..." instead of 24 miles.

Regards,
Greg
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Re: GMAT Diagnostic Test Question 25 [#permalink]

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05 Jan 2014, 22:47
Bunuel wrote:
Distance between the cities $$d$$.

First meeting point $$\frac{d}{2}$$, as both buses travel at the same constant speed and leave the cities same time they meet at the halfway.

Total time to cover the $$d$$ 4 hours, as the buses meet in 2 hours.

On the second day first bus traveled alone 1 hour (36min +24min), hence covered $$0.25d$$, and $$0.75d$$ is left cover.

They meet again at the halfway of $$0.75d$$, which is 24 miles from $$\frac{d}{2}$$:

$$\frac{d}{2}-24=\frac{0.75d}{2}$$

$$d=192$$

I am not sure whether this is a good question...but can we do this problem by plugging in the answer choices...for eg. assumin 'd' to be 192,120...etc??? ..?? is it possible in any way??
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Re: GMAT Diagnostic Test Question 24 [#permalink]

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10 Mar 2014, 14:02
The latest diagnostic test version (v6.2) does not have the exact wording of the original post nor of Bunuel's revision.

I skipped the question when I took the test because I did not know what they were asking. Upon reading the question in this thread, I solved it fairly quickly.
Re: GMAT Diagnostic Test Question 24   [#permalink] 10 Mar 2014, 14:02

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GMAT Diagnostic Test Question 24

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