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# GMAT Diagnostic Test Question 37

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Manager
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Re: GMAT Diagnostic Test Question 37 [#permalink]  01 Nov 2011, 03:53
Total number of balls = 9B+15

Probability of taking a blue ball = B/9B+15

Probability of taking a green ball = 2B+5/9B+15

so probability of taking either a blue ball or a green ball is = (B+(2B+5))/9B+15 = 1/3
Manager
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Re: GMAT Diagnostic Test Question 37 [#permalink]  01 Nov 2011, 10:56
Probability of taking Blue or Green ball = Number of blue and Green balls / total balls in the jar
= B + 2B+5/B + 2B+5 + 6B+10 = 3B+5/9B+15 = 1/3
_________________

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Re: GMAT Diagnostic Test Question 37   [#permalink] 01 Nov 2011, 10:56
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# GMAT Diagnostic Test Question 37

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