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# GMAT Power Prep Test #2 - Qaunt missed

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Intern
Joined: 16 Aug 2006
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GMAT Power Prep Test #2 - Qaunt missed [#permalink]  15 Nov 2006, 19:31
Hi All,

I took my second practice test and missed fewer quant questions than my first test.

I attached a few of the questions i am not 100% on why i missed. Any help you can provide is appreciated!!!!

Thank1
Attachments

gmatprep2_quantmissed.xls [683 KiB]

GMAT Club Legend
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Area of entire medallion = pi (r^2)
Area of glass = pi(r-s)^2

Area of metal frame
= pi(r^2) - pi(r-s)^2
= pi(r^2) - pi(r^2-2rs+s^2)
= 2pi(rs) - pis^2
= pi(s) [2r - s]

Ans E

----------------------------------------------

St1:
sufficient. tells us hundredth digit is 7.

St2:
sufficient. tells us that that the hundreth digit is 7.

Ans D

-----------------------------------------------

Answer has to be 5, since sqrt(5) would be larger than 2 and that would result in an imaginary number.
------------------------------------------------

St1:

For 1/k-1 > 0, k > 1, so 1/k < 0. Sufficient.

St2:

For 1/k+1 > 0, k must be positive since -1 is not a valid possibility. So 1/k < 0. Sufficient.

Ans D
Manager
Joined: 03 Jul 2005
Posts: 194
Location: City
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Kudos [?]: 5 [0], given: 0

For the last question - Question 5

B is insufficent becuase K could be -1/2 and the answer is still greater than 0.
Senior Manager
Joined: 01 Sep 2006
Posts: 302
Location: Phoenix, AZ, USA
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for the root question basically we need to find the number whose root
i greater than 2, in that case root of 2- number greater than 2 will be negative

all values exceot 5 give positive value for 2 - root of number

answer E root of 4 is greater tahn 2

so 2- root of 5 is negative
Intern
Joined: 16 Aug 2006
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ywilfred wrote:
Area of entire medallion = pi (r^2)
Area of glass = pi(r-s)^2

Area of metal frame
= pi(r^2) - pi(r-s)^2
= pi(r^2) - pi(r^2-2rs+s^2)
= 2pi(rs) - pis^2
= pi(s) [2r - s]

Ans E

----------------------------------------------

St1:
sufficient. tells us hundredth digit is 7.

St2:
sufficient. tells us that that the hundreth digit is 7.

Ans D

-----------------------------------------------

Answer has to be 5, since sqrt(5) would be larger than 2 and that would result in an imaginary number.
------------------------------------------------

St1:

For 1/k-1 > 0, k > 1, so 1/k < 0. Sufficient.

St2:

For 1/k+1 > 0, k must be positive since -1 is not a valid possibility. So 1/k < 0. Sufficient.

Ans D

Can you expand on #20? How exactly does each stmt show that the hundreths digit is greater than 5? I am not seeing it.

Senior Manager
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How did you attach the powerprep questions like that?
Intern
Joined: 16 Aug 2006
Posts: 12
Followers: 0

Kudos [?]: 0 [0], given: 0

How did you attach the powerprep questions like that?

when the question is on the screen hit "alt+prnt scrn" to copy it and then paste in excel or word (ctrl+v).
Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

Thanks so much, I've been trying to figure that out for AGES.
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