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GMAT Practice Test 1

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Senior Manager
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GMAT Practice Test 1 [#permalink] New post 13 May 2007, 15:48
Hi All,

Source of the question is: GMAT Prep Test 1

If x is positive which of the following could be correct ordering of 1/x, 2x, x^2.
1) x^2 < 2x < 1/x

2) x^2 < 1/x < 2x

3) 2x < x^2 < 1/x

Choices are:

1) None
2) 1 Only
3) 3 Only
4) I and 2 only
5) 1, 2, 3

Please explain your choices!!!

Thanks
Saurabh Malpani
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 [#permalink] New post 13 May 2007, 16:07
Answer is 2) 1 only

if you place an integer none of the equations will work, but if you place a fraction (1/2 for example) equation 1 will work
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Re: GMAT Practice Test 1 [#permalink] New post 13 May 2007, 20:13
saurabhmalpani wrote:
Hi All,

Source of the question is: GMAT Prep Test 1

If x is positive which of the following could be correct ordering of 1/x, 2x, x^2.
1) x^2 < 2x < 1/x
2) x^2 < 1/x < 2x
3) 2x < x^2 < 1/x

Choices are:

1) None
2) 1 Only
3) 3 Only
4) I and 2 only
5) 1, 2, 3

Please explain your choices!!!

Thanks
Saurabh Malpani



4) I and 2 only


if x =0.1

x^2 2x 1/x
0.0100 0.2000 10.0000



if x = 0.94
x^2 1/x 2x
0.8836 1.0638 1.8800
Senior Manager
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Re: GMAT Practice Test 1 [#permalink] New post 15 May 2007, 07:39
Yes that's the correct answer!!!

Thanks
Saurabh Malpani


Himalayan wrote:
saurabhmalpani wrote:
Hi All,

Source of the question is: GMAT Prep Test 1

If x is positive which of the following could be correct ordering of 1/x, 2x, x^2.
1) x^2 < 2x < 1/x
2) x^2 < 1/x < 2x
3) 2x < x^2 < 1/x

Choices are:

1) None
2) 1 Only
3) 3 Only
4) I and 2 only
5) 1, 2, 3

Please explain your choices!!!

Thanks
Saurabh Malpani



4) I and 2 only


if x =0.1

x^2 2x 1/x
0.0100 0.2000 10.0000



if x = 0.94
x^2 1/x 2x
0.8836 1.0638 1.8800
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 [#permalink] New post 17 May 2007, 02:32
If x is positive which of the following could be correct ordering of 1/x, 2x, x^2.
1) x^2 < 2x < 1/x
2) x^2 < 1/x < 2x
3) 2x < x^2 < 1/x

Choices are:

1) None
2) 1 Only
3) 3 Only
4) I and 2 only
5) 1, 2, 3


another way is to say, 2x will never be greater than x^2. only for x=2, 2x=x^2 and for all other values 2x will be always less than x^2, so we can staright away cancel condition 1 and 2. for x^2 < 1/x will fail when x=1 and satisfies when x=.5 so the condition 3 also fails.

:-D This is my first try in this forum please correct me if my explanation is not good.

H
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 [#permalink] New post 17 May 2007, 06:07
GLADIUS wrote:
If x is positive which of the following could be correct ordering of 1/x, 2x, x^2.
1) x^2 < 2x < 1/x
2) x^2 < 1/x < 2x
3) 2x < x^2 < 1/x

Choices are:

1) None
2) 1 Only
3) 3 Only
4) I and 2 only
5) 1, 2, 3


another way is to say, 2x will never be greater than x^2. only for x=2, 2x=x^2 and for all other values 2x will be always less than x^2, so we can staright away cancel condition 1 and 2. for x^2 < 1/x will fail when x=1 and satisfies when x=.5 so the condition 3 also fails.

:-D This is my first try in this forum please correct me if my explanation is not good.

H


It'd s good try, but you didn't take under consideration the fractions. take x=1/2 :)
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 [#permalink] New post 18 May 2007, 01:26
yes, you are right :)

Thanks for correcting :)

Sergey_is_cool wrote:
GLADIUS wrote:
If x is positive which of the following could be correct ordering of 1/x, 2x, x^2.
1) x^2 < 2x < 1/x
2) x^2 < 1/x < 2x
3) 2x < x^2 < 1/x

Choices are:

1) None
2) 1 Only
3) 3 Only
4) I and 2 only
5) 1, 2, 3


another way is to say, 2x will never be greater than x^2. only for x=2, 2x=x^2 and for all other values 2x will be always less than x^2, so we can staright away cancel condition 1 and 2. for x^2 < 1/x will fail when x=1 and satisfies when x=.5 so the condition 3 also fails.

:-D This is my first try in this forum please correct me if my explanation is not good.

H


It'd s good try, but you didn't take under consideration the fractions. take x=1/2 :)
  [#permalink] 18 May 2007, 01:26
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