vaivish1723 wrote:

I have answered this Q but want to understand the way to solve this.

Isosceles triangle has :

Base = perpendicular = ab = bc

Hypoteneous = ac

ac^2 = ab^2 + bc^2

ac^2 = ab^2 + ab^2

ac^2 = 2ab^2

ac = ab Sqrt(2)

Perimeter of the triangle = ab+bc+ac

16+16(sqrt2) = ab+ ab + ab Sqrt (2)

16 + 8 (sqrt2) + 8 (sqrt2) = ab Sqrt (2) + ab + ab

ab = bc = 8 (sqrt2)

ac = 16

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GT