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# gmat prep-coordinate geometry tough

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gmat prep-coordinate geometry tough [#permalink]  22 Aug 2009, 11:03
1
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64% (01:45) correct 35% (00:56) wrong based on 1 sessions
I've got troubles to answer some of the gmat prep questions. The solutions will be appreciated with kudos . Thanks for the help
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Re: gmat prep-coordinate geometry tough [#permalink]  22 Aug 2009, 13:32
1
KUDOS
we need to find the slope of each line and if k= -1/m then they are perpen

from 1

we can get the slope of line k using the 2 points given and line k is perpend on the x axis slope is undefined, however we cant find the slope of m....insuff

from 2

insuff

both

still insuff

E
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Re: gmat prep-coordinate geometry tough [#permalink]  22 Aug 2009, 13:45
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look at this image, it's better than a long text....
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Just ask if you need more explainations
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Re: gmat prep-coordinate geometry tough [#permalink]  22 Aug 2009, 21:46
From statement 1: line k passes through point (1,-1) since it intersects another line at this point. Also, it is given that line k passes through point (1,1). Therefore, the line k should be of the form x=1 (or parallel to the y axis). Since we do not know anything about the second line, we can't decide if they are perpendicular.
From statement 2: we are given essentially the same information, which is the form of line k: x=1. Line k passes through (1,1) and (1,0). So it must be x=1 or parallel to the y axis. No information about the second line m is given. Not sufficient.
Since both statements give the SAME information, which is not sufficient, the answer is E.
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Re: gmat prep-coordinate geometry tough [#permalink]  23 Aug 2009, 00:06

look at this image, it's better than a long text....
Attachment:
photo.jpg

Just ask if you need more explainations

neat demo.
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Re: gmat prep-coordinate geometry tough [#permalink]  23 Aug 2009, 02:44
IMO ...Nicely explained in the picture....
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Re: gmat prep-coordinate geometry tough [#permalink]  23 Aug 2009, 07:57
When I look at the solution on the picture, line k is parallel to the X axis for the first statement. I might be wrong, but line k passes through the point (1,1) and the point (1,-1) as defined in the first statement...so I thought line k should be parallel to the Y axis?
Am I wrong?
Thank you in advance for the explanation
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Re: gmat prep-coordinate geometry tough [#permalink]  20 Apr 2011, 00:08
perfectstranger wrote:
I've got troubles to answer some of the gmat prep questions. The solutions will be appreciated with kudos . Thanks for the help

a. line k passes through points (1,1) and (1,-1).But line m passes just through (1,-1) and can have any inclination with the x axis. Hence POE a and d.

b. line k passes through points (1,1) and (1,0).But line m can again have any inclination with line k and the x axis. Hence POE b too.

a+b nothing is specified for the inclination of line m. Hence POE C.

Thus E.

thank you.
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Re: gmat prep-coordinate geometry tough [#permalink]  20 Apr 2011, 18:00
amit2k9 wrote:
a. line k passes through points (1,1) and (1,-1).But line m passes just through (1,-1) and can have any inclination with the x axis. Hence POE a and d.

b. line k passes through points (1,1) and (1,0).But line m can again have any inclination with line k and the x axis. Hence POE b too.

a+b nothing is specified for the inclination of line m. Hence POE C.

Thus E.

thank you.

If you look closely, statements 1 and 2 tell you exactly the same thing. So once you understand that statement 1 (or 2) is not sufficient, the other and both combined are automatically not sufficient.
Let me give a simple example to demonstrate:
Ques: What is the value of x?
Stmnt 1: x is 1 or -1
Stmnt 2: x^2 - 1 = 0

Both statements tell you exactly the same thing. Since stmnt 1 is not sufficient to answer the questions, statement 2 will also not be sufficient. Together, they have no new information so they will still not be sufficient.

(And yes, the diagram is incorrect. Stmnt 1: k is parallel to y axis, not x axis. Though, great idea to draw on paper and click it! I spend hours cursing the M Word trying to get my lines in order)
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Re: gmat prep-coordinate geometry tough [#permalink]  20 Apr 2011, 21:47
(1) says the line k has infinite slope

So only way line m can be perpendicular to line k is by having a slope 0

So (1) is insufficient

(2) says that ;

slope of k = infinity

Not Sufficient

(1) and (2) are not sufficient either.

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Re: gmat prep-coordinate geometry tough [#permalink]  21 Apr 2011, 00:26
I dont know how to say this - but my conclusion is divide by zero is meaningless. A line with meaningless slope will be parallel to y axis.

Divide by zero cannot be even compared with divide by zero. Since both the numbers are undefined - i.e. the numbers just don't exist on earth on any planet . So the slopes of line k and m cannot be compared. And any mathematical operation on slopes of k and m is meaningless.
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Re: gmat prep-coordinate geometry tough [#permalink]  21 Apr 2011, 09:23

Since both from I and II we get the same slope for line K (infinity means parallel to Y axis) and have no information on slope of the line M we cannot say for sure whether it is perpendicular or not.
Re: gmat prep-coordinate geometry tough   [#permalink] 21 Apr 2011, 09:23
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