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# gmat prep DS - mode

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Manager
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gmat prep DS - mode [#permalink]

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25 Jun 2007, 05:15
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please explain
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Senior Manager
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25 Jun 2007, 06:17
There are at least 2 different approaches to this problem,
but as to me the best one is PICKing some #s.

1-method)
try x=5,y=2,z=7 and x=-5 , y=7 , z=2 for statement 1 to see
/x/=y-z

2-method)

from the rule of modul:
/x/=y-z then
a) if x>0 then x= y-z or
b) if x<o then x=-(y-z) =z-y so statements 1+2 togather includes
second option (b) completely. Tharefore C

Last edited by UMB on 25 Jun 2007, 11:23, edited 1 time in total.
CIO
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Re: gmat prep DS - mode [#permalink]

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25 Jun 2007, 08:42
Balvinder wrote:
please explain

The first statement says that x + y = z. So x = z - y.

If x is positive, the |x| is also z - y, because nothing changes. If x is negative, then |x| = y - z, because you have to change the sign to make it go positive. Since you don't know about x, you can't know which is right.

Two doesn't say anything on its own, but together, we know that x is negative, so it must be that |x| = y - z.

C
Re: gmat prep DS - mode   [#permalink] 25 Jun 2007, 08:42
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# gmat prep DS - mode

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