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GMAT Prep - DS Probability [#permalink]
 30 Jun 2008, 21:30
Question Stats:
0% (00:00) correct
 0% (00:00) wrong based on 0 sessions
Please explain solution for this question.
Attachments
Prep1 - Probability DS.JPG [ 84.22 KiB | Viewed 524 times ]
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-Albert
My GMAT Preparation: http://albertrahul.blogspot.com/search/label/GMAT
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Re: GMAT Prep - DS Probability [#permalink]
30 Jun 2008, 22:49
E
We need to find the actual number of balls of each color and/or odd/even.
statement 1 is obviously not enough because it does not give the number of white balls
statement 2 is not enough because you can have (10 white balls) - (5 evens) = 6 OR 15 white balls - 10 evens = 5 (which is 20%)
Put them together, still not enough to solve because we still don't know how many white balls there are.
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Re: GMAT Prep - DS Probability [#permalink]
30 Jun 2008, 23:16
I would guess E but I am not really sure of any method to get around this. I would appreciate if someone could make a detailed explanation.
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Re: GMAT Prep - DS Probability [#permalink]
02 Jul 2008, 08:49
Is the Answer is C?
Please post the OA...
Not sure of the explanation, if the answer is C, then I will post my explation...
Thanks
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Re: GMAT Prep - DS Probability [#permalink]
02 Jul 2008, 09:09
the answer is E.
question: what's the combined number of white balls and balls with even numbers = #(white) + #(even) - #(white and even)
1) there are not white balls with even numbers (#white and even) = 0
2) the number of white balls is the number of even numbers + 5: #(white) = #(even) + 5
1&2: insufficient #white = 6, #even = 1 or #white = 7 and # even = 2
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Re: GMAT Prep - DS Probability [#permalink]
02 Jul 2008, 09:50
OA is E. Thank you all for explanation.
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-Albert
My GMAT Preparation: http://albertrahul.blogspot.com/search/label/GMAT
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Re: GMAT Prep - DS Probability
[#permalink]
02 Jul 2008, 09:50
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