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# GMAT -Prep Ps2

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GMAT -Prep Ps2 [#permalink]  21 Dec 2008, 07:56
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Re: GMAT -Prep Ps2 [#permalink]  21 Dec 2008, 08:15
vivektripathi wrote:
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Since x is not equal to 0, x could be -ve or +ve.

lxl/x should be true.

if x is +ve, lxl/x = l1l/1 =1.
if x is -ve, lxl/x = l-1l/-1 =-1.

so E.
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Re: GMAT -Prep Ps2 [#permalink]  22 Dec 2008, 17:14
To avoid the complications that can come with the ugly positives and negative signs, wouldn't it be easier to treat this question as an exponentials one?

root of x-squared = change to x-squared to the power of (1/2) = x to the power of (1/2 multiplied by 2) = x to the power of 1.

then bring the denominator up to the numerator:
x in the denominator = x to the power of (-1) in the numerator

SO
now numerator is [x to the power of 1] multiplied by [x to the power of (-1)]
= x to the power of [1 + (-1)]
= x to the power of 0
= 1.

Ans: C
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Re: GMAT -Prep Ps2 [#permalink]  22 Dec 2008, 17:37
sidrah wrote:
To avoid the complications that can come with the ugly positives and negative signs, wouldn't it be easier to treat this question as an exponentials one?

root of x-squared = change to x-squared to the power of (1/2) = x to the power of (1/2 multiplied by 2) = x to the power of 1.

then bring the denominator up to the numerator:
x in the denominator = x to the power of (-1) in the numerator

SO
now numerator is [x to the power of 1] multiplied by [x to the power of (-1)]
= x to the power of [1 + (-1)]
= x to the power of 0
= 1.

Ans: C

Agree with E

$$sqrt(x^2)= |x|$$
$$e.g sqrt(4) = +2 or -2$$
$$4= 2^2 or (-2)^2$$
$$sqrt(4)=|2|$$
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Re: GMAT -Prep Ps2   [#permalink] 22 Dec 2008, 17:37
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