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GMAT PREP q1

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GMAT PREP q1 [#permalink] New post 27 Aug 2006, 03:22
GMAT PREP q

Please explain your ans
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 [#permalink] New post 27 Aug 2006, 10:03
C for me.
If we can find the x and y intercepts then we can determine if the line intersects the circle.
From St1. and St2. y-intercept is 1/10. So we can say the line intersects the circle even if x >1.
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 [#permalink] New post 27 Aug 2006, 10:33
I think it is E
say, the eq of line k is y= mx +c

from 1) we know x intercept is greater than 1.
mx + c = 0 ; x = -c/m or -c/m > 1 => c is negative or m is negative
we don't know either INSUFF

from 2) m = -1/10 the slope is negative but nothing about the intercepts so INSUFF

combined. -c/(-1/10) > 1 or 10c> 1; c is positive but can be any value so INSUFF
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 [#permalink] New post 27 Aug 2006, 11:42
IMHO .. the answer is E ... we can't find anything concrete to make a conclusion
1) says x-intercept > 1 .. we need to know y intercept also --Insufficient
Eliminate A and D

2) says slope = -1/10
=> y = -1/10*x + c
=> x-intercept = 10*c ...c (y-intercept) could be anything thus can't make any conclusion
Eliminate B)

1) & 2)
Now x > 1 and x = 10c
=>c >1/10 ...
we neede something like a<c<b ..so that we can infer whether y-intercepy>1 or <1 ... we don't find any information from these two statements ..
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 [#permalink] New post 27 Aug 2006, 11:43
IMHO .. the answer is E ... we can't find anything concrete to make a conclusion
1) says x-intercept > 1 .. we need to know y intercept also --Insufficient
Eliminate A and D
2) says slope = -1/10
=> y = -1/10*x + c
=> x-intercept = 10*c ...c (y-intercept) could be anything thus can't make any conclusion Eliminate B)
1) & 2)
Now x > 1 and x = 10c => c >1/10 ...
we neede something like a<c<b
so that we can infer whether y-intercepy>1 or <1
we don't find any information from these two statements.
Elimainate C
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 [#permalink] New post 28 Aug 2006, 21:42
(1)The line may or maynot intersect. Without knowing the slope insuff
BCE

(2) slope = -1/10
co-ordinates of end points of the line could be (0,1) & (10,0) Hence line would intersect the circle
Suff

B

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 [#permalink] New post 04 Sep 2006, 08:27
Hemen

The answer is C, the slope only is not enough to determine where the line crosses the X & Y axis.

1) gives a point on the line (1,0)
2) gives the slope of the line

hence the equation of theline if (y-y1)=m(x-x1)

simplified => 10y+x = 1 . Now this line can be plotted in only one way , hence C
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 [#permalink] New post 05 Sep 2006, 07:44
I'll have to take (E) on this one. Try picking large and small numbers for a set of (x,y) coordinates and the outcome differs.
  [#permalink] 05 Sep 2006, 07:44
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