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Re: GMAT Prep Similar Triangles [#permalink]
I am not good at solving via equations on these types of problems so I tried picking numbers. I assumed both triangles were a 45-45-90 triangle to make things easy...

I picked 4 for a "side" on the smaller one which would make the area =8.
For the larger once, since it was twice the area, I said each side was sqrt32 which would make the area 16...

When I do that and solve, the answer doesn't come out to choice c...because the answer is not sqrt2*4

Can't I pick numbers for this problem?
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Re: GMAT Prep Similar Triangles [#permalink]
ps_dahiya :

SH = 2sh
Let S = ks
so H = kh

i.e k^2 * sh = 2sh
k^2 = 2
k = SQRT(2)
S = s* (SQRT(2)

could you explain s = ks concept. I'm not getting it. thanks
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Re: GMAT Prep Similar Triangles [#permalink]
alimad wrote:
ps_dahiya :

SH = 2sh
Let S = ks
so H = kh

i.e k^2 * sh = 2sh
k^2 = 2
k = SQRT(2)
S = s* (SQRT(2)

could you explain s = ks concept. I'm not getting it. thanks

Both triangles are similar triangles because their angles are same.
So the ratio of their corresponding sides will be same
So I assumed S/s = k
Read more about similar triangles here:

https://regentsprep.org/Regents/math/si ... imilar.htm



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