Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 28 Apr 2015, 02:32

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# GMAT Prep Similar Triangles

Author Message
TAGS:
Intern
Joined: 02 May 2006
Posts: 25
Followers: 0

Kudos [?]: 0 [0], given: 0

GMAT Prep Similar Triangles [#permalink]  26 Jul 2006, 08:59
How can I afront this question?

Thanks
Attachments

File comment: SP 2

SP 2.JPG [ 51.94 KiB | Viewed 705 times ]

VP
Joined: 02 Jun 2006
Posts: 1267
Followers: 2

Kudos [?]: 42 [0], given: 0

It is evident that the two triangles are similar. In which case the ratio of the base to the height of one is equal to the ratio of the base to height of the other

i.e. S/H = s/h => s/S = h/H

Given SxH/2 = 2xsxh/2

or SH = 2sh

S= 2sx h/H=2s x s/S

S^2 = 2s^2

or S = s x sqrt(s)
CEO
Joined: 20 Nov 2005
Posts: 2913
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 18

Kudos [?]: 119 [0], given: 0

C

Since the triangles are similar. Ratios of their corresponding sides are equal.

SH = 2sh
Let S = ks
so H = kh

i.e k^2 * sh = 2sh
k^2 = 2
k = SQRT(2)
S = s* (SQRT(2)
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Senior Manager
Joined: 02 May 2004
Posts: 313
Followers: 1

Kudos [?]: 6 [0], given: 0

I am not good at solving via equations on these types of problems so I tried picking numbers. I assumed both triangles were a 45-45-90 triangle to make things easy...

I picked 4 for a "side" on the smaller one which would make the area =8.
For the larger once, since it was twice the area, I said each side was sqrt32 which would make the area 16...

When I do that and solve, the answer doesn't come out to choice c...because the answer is not sqrt2*4

Can't I pick numbers for this problem?
Director
Joined: 10 Feb 2006
Posts: 664
Followers: 3

Kudos [?]: 119 [0], given: 0

ps_dahiya :

SH = 2sh
Let S = ks
so H = kh

i.e k^2 * sh = 2sh
k^2 = 2
k = SQRT(2)
S = s* (SQRT(2)

could you explain s = ks concept. I'm not getting it. thanks
_________________

GMAT the final frontie!!!.

CEO
Joined: 20 Nov 2005
Posts: 2913
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 18

Kudos [?]: 119 [0], given: 0

ps_dahiya :

SH = 2sh
Let S = ks
so H = kh

i.e k^2 * sh = 2sh
k^2 = 2
k = SQRT(2)
S = s* (SQRT(2)

could you explain s = ks concept. I'm not getting it. thanks

Both triangles are similar triangles because their angles are same.
So the ratio of their corresponding sides will be same
So I assumed S/s = k

http://regentsprep.org/Regents/math/sim ... imilar.htm
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Similar topics Replies Last post
Similar
Topics:
2 Determining the Area of Similar Triangles on the GMAT 1 18 Feb 2015, 04:00
5 Looking for Similar Triangles on the GMAT 1 11 Feb 2015, 05:54
1 Similar Triangles 3 02 May 2010, 15:56
good one - similar triangles Gmat Prep 4 02 Jan 2007, 12:57
GMAT Prep: Similar Triangles 4 06 Dec 2005, 13:19
Display posts from previous: Sort by