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GMAT prep test 5

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Senior Manager
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GMAT prep test 5 [#permalink] New post 27 Jan 2010, 09:48
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

67% (01:44) correct 33% (00:28) wrong based on 2 sessions
Please, explain...
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Re: GMAT prep test 5 [#permalink] New post 27 Jan 2010, 14:03
imagine line K extending from (1,1) intersecting the x axis at 1 ,and reachig point (1,-1) and quadrant IV.
now line M meets k at (1 , -1) but we dont know to which direction its sloping , could be horizontal at y = -1 or it could be -vely sloped . That doesnt tell us whether the 2 lines are perpindiclar
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Re: GMAT prep test 5 [#permalink] New post 27 Jan 2010, 16:50
To determine if the lines are perpendicular we need to know the slopes of the two lines. Two points are given for line k but only one point is given for line l so it is impossible to find the slope of line l. The two points help us find rise/run which is the slope.


The lines would be perpendicular if the slops of the two lines are negative reciprocals of each other.

Answer: E
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Re: GMAT prep test 5 [#permalink] New post 27 Jan 2010, 20:06
mirzohidjon wrote:
Please, explain...


I'll tell you what your mistake was.

You calculated line K's slope as -infinity and for line m, though it's the same point, you might not have recognized it in your hurry and solved for slope consider the same point as twice, giving you a +infinity as slope. So obviously, they seem perpendicular but actually, product of slopes of perpendicular intersecting lines is supposed to be -1, and we are not sure if product of two infinities is 1.
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Re: GMAT prep test 5 [#permalink] New post 27 Jan 2010, 21:20
Thanks for posting.
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Re: GMAT prep test 5 [#permalink] New post 15 Feb 2010, 04:36
ans is e

to lines will be perpendicular when the product of the slopes of that 2 lines yield -1.

both the stmts don't satisfy the above criteria
Re: GMAT prep test 5   [#permalink] 15 Feb 2010, 04:36
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