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I have 9 clients that I tutor in person, and have a waiting list as well, so I'm quite busy : )
With a 770 you can definitely tutor.
I'm going to do a GMATPrep right now, I have 2 hours to kill.... to be continued.
How much do you charge? And how exactly do you tutor them? Are you with them at all times when they are doing exercises or do they just come to you when they don't understand?
How much money do you make per client on average?
How do you advertise your services? Word of mouth?
Ok, very happy! Wrote gmatprep2, very hung over mind you,
800 51Q (2x) 51V (0x)
Quant finished in 62 mins, Verbal well under time...
And, I got this question. i said it was E.
If N & P are integers, is p>0?
1) N + 1 > 0 2) NP > 0
Now, consider the case n=-1/2, p=-1/2, and n=1/2, p=1/2
N+1>0 in both cases, and NP>0 in both cases. In one case p < -1/2, and p > 1/2. Hence I said E. But..... I'm an idiot and didn't consider that N & P are integers. Blah. Easy question.
And I got a good one wrong: If M is an odd positive integer between 2 & 30, then how many different prime numbers is M divisible by? 1) M is not divisible by 3 2) M is not divisible by 5
I said C, OA was A. Oops... I forgot that 25 only has 1 prime factor (I was thinking 2). Missed the 'different' word.
So the 2 were stupid mistakes,
I'm writing Monday. 12:15pm. I'm ready : )
I have to tutor someone now, so I won't reply for a bit... but I'll type up a solution to that question.
999=801+(n-1)(3) (kind of using the progression sum approach)
999-801=3n-3 198+3=3n 201=3n n=67
how do you get 72 or 71????
apurva1985 wrote:
Plz can you tell me a place from where i can review some advanced number system questions...............i am struggling with it. Like the question was how many 3 digit no.s greater than 800 will be divisible by 3 i tried solving it by this method (999-801)/3 = 66 but the answer is 72 i suppose...... can you please expain it
StartupAddict wrote:
I have 9 clients that I tutor in person, and have a waiting list as well, so I'm quite busy : )
With a 770 you can definitely tutor.
I'm going to do a GMATPrep right now, I have 2 hours to kill.... to be continued.
Oh congrats on the 770. Your GMATPrep's were quite accurate : )
Where are you located? If you're near big cities you can charge a nice rate. Be aware though that a lot of the time you're not going to be teaching, say for example how many different prime factors N has if 14n/200 is integer and N<200..... You're going to be attempting to explain the concept of a variable or what prime numbers are, or exponent rules..... most people don't know the basics. This is where my Math degree comes in handy definitely... although I have tutored the other type too, the ones scored got 700+... over 15 so far.
Kevincan, ughm, I don't know haha. I drink a lot. Definitely not getting wasted Sunday night Not like last time... or will I?
Oh congrats on the 770. Your GMATPrep's were quite accurate : )
Where are you located? If you're near big cities you can charge a nice rate. Be aware though that a lot of the time you're not going to be teaching, say for example how many different prime factors N has if 14n/200 is integer and N<200..... You're going to be attempting to explain the concept of a variable or what prime numbers are, or exponent rules..... most people don't know the basics. This is where my Math degree comes in handy definitely... although I have tutored the other type too, the ones scored got 700+... over 15 so far.
Kevincan, ughm, I don't know haha. I drink a lot. Definitely not getting wasted Sunday night Not like last time... or will I?
I'm located about 35 minutes out of Montreal...
Either way I'll have to think about this. Could be a good way to make a decent amount of cash while networking a little bit.
I dont know if the OA is right one more thing if i have a conditon added to it that all the 3 digits should be different than what will be the method to solve it
StartupAddict wrote:
Here's my solution:
How many 3 digit integers greater than 800 are divisible by 3?
We're looking at 801 - 999 basically.
So 801, 804, 807, etc.
There are 999 - 801 + 1 = 199 numbers between 801->999. So 801 is divisible by 3, So we want the greatest integer value for 801 + 3X less than 1000
Playing around with it.... So 801 + 3X < 1000
3X < 199 X < 67
X = 66.
Now we have to remember that X starts at 0, so the values are 0 -> 66, or 67 values.
There are 67 3-digit #'s bigger than 800 divisible by 3
Got 1 RC wrong, 2 SC. Did the SC in 16 mins instead of 25-- rushed, would have gotten the 2 right had I spent more time. Anyways, scales to 103.75/107, 103/107, 102+ is 800. So I still got an 800... everything else was under time too. Did the DS in 14 minutes instead of 25, the paper test math is much easier than the CAT of course...
2 800's in a row... will do GMATPrep1 tomorrow. I'm writing Monday @ noon. Hoping for 780 at the very least.
Both of the Quant questions I didn't spend enough time on. The SC was close, I had it down to 2, 50/50. I went with the shorter one, but it was an illogical comparison error. The other one had 'their' and the sentence had two plural objects, so I decided the shorter one was the lesser of two evils, but apparently not.
Aren't you getting some repetitions by now? After all, you are tutoring as well and must have seen nearly everything by now. I never find new quant questions (though I have seen about 100 GMATPrep exams)
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