Hi guys,

Sorry, couldn't see the discussion for Q7 in M01 and neither could add the discussion anywhere else.

Although I answered this question correctly, I need a help in solving this problem in the quicker way

Question Number 7

A ship is transporting several cats and a crew (sailors, a cook, and a one-legged captain) to a nearby port. If these passengers combined have 15 heads and 41 legs, then how many cats is the ship transporting?

* 3

* 5

* 6

* 7

* 8

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My explanation for this question is:

Let's denote A- cats, B- Sailors ( Don't fall into trick , as Sailors is in plural), C- cook =1, and D- captain-=1 ( and one legged)

thus we have : a+b+1+1= a+b+2 people on the board

We know that there are 15 Heads in total THUS,

a+b+2=15 heads

or

a+b=13or b=13-a

We also know that there are 41 legs in total,

Bear in mind that cats ( A) have 4 legs, and captain has 1 leg , equations is as follows:

4a+2b+2+1=41

4a+2b=38

Substitute from 1st equation:

2(2a+b) =38

2a+b=19

2a+(13-a)=10

a=6

thus C

IF you have any shorter solutions please share !

Thanks in advance

_________________

TimurGMAT CRASHER