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# GMATPrep 18 equally qualified applicants for 4 open position

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Manager
Joined: 30 May 2010
Posts: 190
Followers: 3

Kudos [?]: 35 [0], given: 32

GMATPrep 18 equally qualified applicants for 4 open position [#permalink]  07 Sep 2010, 09:47
00:00

Difficulty:

5% (low)

Question Stats:

92% (01:44) correct 7% (00:41) wrong based on 13 sessions
A certain company has 18 equally qualified applicants for 4 open positions. How many different groups of 4 applicants can be chosen by the company to fill the positions if the order of selection does not matter?

(A) 18
(B) 72
(C) 180
(D) 1,260
(E) 3,060
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 16878
Followers: 2776

Kudos [?]: 17637 [1] , given: 2233

Re: GMATPrep 18 equally qualified applicants for 4 open position [#permalink]  07 Sep 2010, 09:59
1
KUDOS
Expert's post
jpr200012 wrote:
A certain company has 18 equally qualified applicants for 4 open positions. How many different groups of 4 applicants can be chosen by the company to fill the positions if the order of selection does not matter?

(A) 18
(B) 72
(C) 180
(D) 1,260
(E) 3,060

# of ways to choose 4 different people out of 18, when order of chosen people doesn't matter is C^4_{18}=\frac{18!}{14!*4!}=3060.

_________________
Re: GMATPrep 18 equally qualified applicants for 4 open position   [#permalink] 07 Sep 2010, 09:59
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