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GMATPrep Arithmetic mean and median

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GMATPrep Arithmetic mean and median [#permalink] New post 21 Sep 2006, 18:34
Please explain how to solve this problem

A list of measurements in increasing order is 4,5,6,8,10 and X.If the median of these measurements is 6/7 times their arithmetic mean, what is the value of X?

The correct answer is 15.
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Re: GMATPrep Arithmetic mean and median [#permalink] New post 21 Sep 2006, 20:34
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Olivia wrote:
Please explain how to solve this problem

A list of measurements in increasing order is 4,5,6,8,10 and X.If the median of these measurements is 6/7 times their arithmetic mean, what is the value of X?

The correct answer is 15.


median = (6+8)/2 = 7
mean = (4+5+6+8+10+x)/6

median = 6/7 (mean)
7 = (6/7) {(4+5+6+8+10+x)/6}
x = 49 - (4+5+6+8+10)
x = 49 - (33)
x = 16

hope i didnot do any wrong calculations...........
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 [#permalink] New post 22 Sep 2006, 00:40
Don't see how it could possibly be 15 - I used same calc as Professor and got 16.
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 [#permalink] New post 22 Sep 2006, 01:20
A list of measurements in increasing order is 4,5,6,8,10 and X.If the median of these measurements is 6/7 times their arithmetic mean, what is the value of X?


MEDIAN = 6+8 / 2 = 7

Mean = 33+x / 6

Median = 6/7(33+x / 6 ) = 7

6(33+x) / 42 = (33+x) / 7 = 7.....ie: 33+x = 49 thus x = 16

Olivia no way this could be 15
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 [#permalink] New post 22 Sep 2006, 05:02
Thank you very much for explanation.
I am sorry the correct answer is 16. I just wrote the wrong number.
  [#permalink] 22 Sep 2006, 05:02
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