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GMATPREP:DS2

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GMATPREP:DS2 [#permalink] New post 29 Apr 2008, 22:22
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please explain your answers
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Re: GMATPREP:DS2 [#permalink] New post 30 Apr 2008, 08:41
ok since I am going to have to do these bloody questions again, let me give it a shot

1. sufficient, because -2x > any positive number if x is also negative.
Eliminate choices BCE
2. insufficent, can be rewritten as 2x+5y = 20 - this opens itself to all possibilities ... X could be positive, y could be positive or x could be negative and y could be positive, or x could be positive and y could be negative.

Consequently - A is the correct answer.

Do enlighten me with the OA whenever you get some more responses.
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Re: GMATPREP:DS2 [#permalink] New post 30 Apr 2008, 10:00
I fell for A trap too :-) incorrect ! waiting for more responses
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Re: GMATPREP:DS2 [#permalink] New post 30 Apr 2008, 12:25
I think the ans is D.
Second cond is also suff.

y<(-2/3)x

20 = 2x+5y < 2x-(10/3)x = (-4/3)x

Hence, (-4/3)x > 20
-x>15
x<-15

Hence x is always negative
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Re: GMATPREP:DS2 [#permalink] New post 30 Apr 2008, 12:35
rpmodi wrote:
please explain your answers


I get D.

1 is pretty obvious.

2: you realize that one of the two MUST be positive. or else it wont equal to 20.
Re: GMATPREP:DS2   [#permalink] 30 Apr 2008, 12:35
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