I also agree wity Murti's solution, except for the conclusion.

Given y >= 0

From #2. -y >= |x-3|

|x-3| -- Absolute value -- is always +ve or 0

-y >=0 & y >=0 can only be possible if y = 0.

Hence |x-3| = 0 or x = 3 SUFF.

From #1 y <=|x-3| x & y can take any value as long as 0=<y<|x-3|

INSUFF to find x.

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