GmatPrep - Inequality : Quant Question Archive [LOCKED]
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# GmatPrep - Inequality

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18 Jun 2006, 06:49
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Last edited by gmat_crack on 07 Jul 2008, 19:54, edited 1 time in total.
VP
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18 Jun 2006, 08:08
Should be B. since y>=0, -y cannot be >lx-3l, which is always +ve or 0. ..

therefore, x = 0.
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18 Jun 2006, 18:25
I dont quite uniderstand,

in stmt 2, if Ix-3I<= -Y if you take x=0 then Ix-3I =3 which CANT be lesser than -Y because Y has to be >=0 and has a negative sign.
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18 Jun 2006, 18:39
Strange, we're told y is positive, so -y must be negative. |x-3| is a modula operation, which always gives a positive result. How can a positive be less than or equals to a negative? (Statement 2)
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18 Jun 2006, 19:21
I also agree wity Murti's solution, except for the conclusion.
Given y >= 0
From #2. -y >= |x-3|
|x-3| -- Absolute value -- is always +ve or 0
-y >=0 & y >=0 can only be possible if y = 0.
Hence |x-3| = 0 or x = 3 SUFF.

From #1 y <=|x-3| x & y can take any value as long as 0=<y<|x-3|
INSUFF to find x.
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VP
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18 Jun 2006, 20:24
MA wrote:
Should be B. since y>=0, -y cannot be >lx-3l, which is always +ve or 0. ..

therefore, x = 0.

x = 3. that was a typo.
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18 Jun 2006, 23:39
Ans is B.

Since y >= 0, |x-3| <= -y. The value has to be 0. So x = 3.

In A there are a myriad possibilities.
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Thanks,
Zooroopa

18 Jun 2006, 23:39
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