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Senior Manager
Joined: 08 Jun 2004
Posts: 499
Location: Europe
Followers: 1

Kudos [?]: 20 [0], given: 0

Attachments

Prob_Leo.doc [64.5 KiB]

Manager
Joined: 27 Jan 2006
Posts: 156
Location: Europe
Followers: 1

Kudos [?]: 2 [0], given: 0

d) 0.657 ?

the probability that A plays song that Leo does't like = 7/10
the probability that B plays song that Leo does't like = 7/10
the probability that C plays song that Leo does't like = 7/10

0.7^3 = 0.343

1-0.343 = 0.657
_________________

Stay hungry, Stay foolish

VP
Joined: 21 Sep 2003
Posts: 1066
Location: USA
Followers: 3

Kudos [?]: 39 [0], given: 0

Agree it should be D.

P(Listening to a song) = 1 - P(Not listening to song on A or B or C) = 1- {7/10*7/10*7/10} = 657/1000
_________________

"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."

- Bernard Edmonds

Director
Joined: 06 May 2006
Posts: 781
Followers: 3

Kudos [?]: 16 [0], given: 0

Yep. Looks like D. as per explanations abov.
Senior Manager
Joined: 08 Jun 2004
Posts: 499
Location: Europe
Followers: 1

Kudos [?]: 20 [0], given: 0

Yes guys OA is D 0.657.

Thank you for explanations.
SVP
Joined: 30 Mar 2006
Posts: 1739
Followers: 1

Kudos [?]: 46 [0], given: 0

another approach

Probability that A plays the right music = 0.3
Probability that B plays the right music = 0.7*0.3 = .21
Probabiltiy that C plays the right music = 0.7*0.7*0.3 = .147

Total = 0.657
CEO
Joined: 20 Nov 2005
Posts: 2913
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 18

Kudos [?]: 119 [0], given: 0

jaynayak wrote:
another approach

Probability that A plays the right music = 0.3
Probability that B plays the right music = 0.7*0.3 = .21
Probabiltiy that C plays the right music = 0.7*0.7*0.3 = .147

Total = 0.657

This is exaxtly the approach I used.
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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