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Manager
Joined: 14 May 2006
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Hi, I am new here. Great site by the way. Got the below question on GMATPrep today and couldn't figure out:
Q: A certain city with a population of 132,000 is to be divided into 11 voting districts, and no district is to have a population that is more than 10% greater than the population of any other districts. What is the minimum possible population that the least populated district could have?
10,700
10,800
10,900
11,000
11,100
Cheers,
SJ
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Director
Joined: 08 Jun 2004
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Location: Europe
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11,000 it is.
X - the least populated district could have.
1.1 X - no more than 10% + to the population of any other districts, so
X+10(1.1X) = 132,000
12X=132000
X=11,000
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Intern
Joined: 23 Feb 2006
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I think it's 10900. Solution:
x/1.1+10*x=132000 => x=12100 => x/1.1=10909
The possible mistake could happen if one take
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Intern
Joined: 23 Feb 2006
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I'm sorry - made a rounding error...
12*x=145200 => x=145200/12=12.1 and then cheapest 12.1/1.1=11
11 is an answer
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Manager
Joined: 17 Jan 2006
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i got 10,800
132,000/11 * 0.9 = 10,800
what is the OA?
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Director
Joined: 24 Oct 2005
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Location: London
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Got 11000.
1 district minimum population = x
Remaining 10 districts - Max population =10% greater than x
Same method as M8.
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Manager
Joined: 14 May 2006
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OA is 11000. Thanks everyone.
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