GMATPrep Question: Half Circle : Quant Question Archive [LOCKED]
Check GMAT Club App Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

It is currently 04 Dec 2016, 14:17
GMAT Club Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

GMATPrep Question: Half Circle

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Manager
Manager
avatar
Joined: 13 Mar 2007
Posts: 98
Followers: 1

Kudos [?]: 31 [0], given: 0

GMATPrep Question: Half Circle [#permalink]

Show Tags

New post 10 Nov 2007, 17:21
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi, if you know how to solve this problem and you can explain your answer. Please let me know. Also, if you know any shortcut method regarding this question, please let me know too.

I have already looked at the following link, but I still do not get it. http://www.gmatclub.com/forum/t22425
Attachments

gmatperp_question.GIF
gmatperp_question.GIF [ 5.22 KiB | Viewed 831 times ]

Director
Director
User avatar
Joined: 13 Dec 2006
Posts: 518
Location: Indonesia
Followers: 6

Kudos [?]: 207 [0], given: 0

 [#permalink]

Show Tags

New post 10 Nov 2007, 17:46
Solution:

Lets say A and B are two points on circle with coordinates (-sqrt3, 1) and (s,t) respectively. Their distance from the center of the circle, origin in this case will be the same, as it is the radius of the circle.

applying the formula to calculat the distance we will have radius of the circle to be 2. so we have s^2 + t^2 = 4... equation 1.

Also we know that these two lines make right angle at origin. By applying pythagoras them, we have (s+sqrt3)^2 + ( t-1)^2) = 8

On solving and using equation 1, we will get t = sqrt3 * S

Now again putting this value in equation 1, we get s = 1

Amardeep
  [#permalink] 10 Nov 2007, 17:46
Display posts from previous: Sort by

GMATPrep Question: Half Circle

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.