GmatPrepTest2-Question5 : Quant Question Archive [LOCKED]
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# GmatPrepTest2-Question5

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GmatPrepTest2-Question5 [#permalink]

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22 Feb 2009, 14:54
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Re: GmatPrepTest2-Question5 [#permalink]

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22 Feb 2009, 16:43
Here is my approach.......

It is given that there are 23 cent costing pencil and 21 cent costing pencil.

From stmt 1, it given that there are 6 pencils in total. From here we cannot say how many 23 cent pencils are there. It can range from 1 to 6. So insufficient.

From stmt 2, it is given the total cost pencils is 130. This means 23x + 21y = 130. Hum one eq and two variables......Is it cannot solve? Wait a minute......Can we not figure out some random guesses. We should know that here x and y are integers since they represent the number of pencils of each cost.

So we can have at the max 4 - 23 cents costing pencils. So the ans for x will be such that 1<=x<= 4 and 130-23x is divisible by 21. definitely we can find the value of x. Hence sufficient.

IMO B.
Re: GmatPrepTest2-Question5   [#permalink] 22 Feb 2009, 16:43
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# GmatPrepTest2-Question5

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