Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Guests at a recent party ate a total of fifteen hamburgers. [#permalink]
18 Nov 2009, 20:47

3

This post received KUDOS

15

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

85% (hard)

Question Stats:

53% (02:29) correct
47% (01:43) wrong based on 287 sessions

Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger. No hamburger was eaten by any guest who was a student, a vegetarian, or both. If half of the guests were vegetarians, how many guests attended the party?

(1) The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians.

(2) 30% of the guests were vegetarian non-students.

Re: Guests at a recent party ate a total of fifteen hamburgers. [#permalink]
19 Nov 2009, 04:46

2

This post received KUDOS

1

This post was BOOKMARKED

kairoshan wrote:

Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger. No hamburger was eaten by any guest who was a student, a vegetarian, or both. If half of the guests were vegetarians, how many guests attended the party?

(1) The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians.

(2) 30% of the guests were vegetarian non-students.

Good question.

Question Stem : Total number of people attending the party , x = students + vegetarians + neither - both Also, vegetarians = x/2 (this implies that non vegetarians also = x/2) And, NVnonstudents = 15

St. (1) : Vstudents/ Vnonstudents = 2/3 ; NVstudents/NVnonstudents = 4/3 The second ratio gives us NVstudents = 20 Therefore total Non Vegetarians = 20 + 15 = 35 This accounts for half the number of people at the party. This total number of people = 70 Hence, Sufficient.

St. (2) : 30% were Vnonstudents. By itself, this statement gives us nothing. Hence, Insufficient.

Re: data suffeciency [#permalink]
09 Nov 2010, 11:15

First of all, we need to be able to find a solid number,the total number of guest, as an answer.

The only solid number we are given to work with is 15, the number of hamburgers eaten by the guests.

From the question we could see that the guests can be broken down into 4 categories.

VEGETARIAN STUDENT (V & S) NON-VEGETARIAN STUDENT (NV & S) VEGETARIAN NON-STUDENT (V & NS) NON-VEGETARIAN NON-STUDENT (NV & NS)

Looking @ # of hamburgers eaten,

The question states that (NV & NS) ate exactly 1 hamburger and that no hamburger was eaten by any guest who was a student, hamburger eaten by (V & S) = (NV & S) = 0; a vegetarian, hamburger eaten by (V & S) = (V & NS) =0; or both, hamburger eaten by (V & S) = 0.

So from this we can conclude the # of (NV & NS) = 15.

The last piece of information given is that 1/2 Total = V, which also means 1/2 Total = NV, where NV + V = Total and NS + S = Total. Drawing a table can help understand this relationship.

Statement 1:

The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians.

I think this should be reworded to ratio instead of rate.

Anyways this just means that for every 2 (V & S) there are 3 (V & NS), which is half the ratio of S to NS for NV. Therefore for every 4 (NV & S) there are 3 (NV & NS), which means \(\frac{4}{3}=\frac{(NV & S)}{(NV & NS)}\)

Since we know that (NV & NS) = 15. We can solve for (NV & S) and Find Total because 1/2* Total = (NV & NS) + (NV & S)

Sufficient.

Statement 2:

30% of the guests were vegetarian non-students.

This give us no way to link 15 to the total number of guest. So insufficient.

This is more clear if you draw a table to help visualize things.

I'm sure someone will come up with a better explanation later, but I hope this can help till then.

Last edited by chaoswithin on 09 Nov 2010, 11:24, edited 2 times in total.

Re: data suffeciency [#permalink]
09 Nov 2010, 11:19

10

This post received KUDOS

Expert's post

mrinal2100 wrote:

Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger. No hamburger was eaten by any guest who was a student, a vegetarian, or both. If half of the guests were vegetarians, how many guests attended the party?

(1) The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians.

(2) 30% of the guests were vegetarian non-students.

can someone explain in detail

We have 4 groups of guests: 1. Vegetarian students; 2. Vegetarian non-students; 3. Non-vegetarian students; 4. Non-vegetarian non-students.

Now, as guests ate a total of 15 hamburgers and each guest who was neither a student nor a vegetarian (group #4) ate exactly one hamburger and also as no hamburger was eaten by any guest who was a student, a vegetarian, or both (groups #1, #2 and #3) then this simply tells us that there were 15 non-vegetarian non-students at the party (group #4 = 15).

Make a matrix:

Attachment:

Stem.PNG [ 2.33 KiB | Viewed 11932 times ]

Note that we denoted total # of guests by \(x\) so both vegetarians and non-vegetarians equal to \(\frac{x}{2}\).

(1) The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians --> \(\frac{vegetarian \ students}{vegetarian \ non-students}=\frac{2}{3}\) --> if the rate X (some fraction) is half of the rate Y (another fraction), then Y = 2*X --> \(\frac{non-vegetarian \ students}{non-vegetarian \ non-students}=2*\frac{2}{3}=\frac{4}{3}\) --> so, non-vegetarian non-students compose 3/7 of all non vegetarians: \(non-vegetarian \ non-students = 15 = \frac{3}{7}*\frac{x}{2}\) --> \(x=70\). Sufficient.

Attachment:

1.PNG [ 2.59 KiB | Viewed 12027 times ]

(2) 30% of the guests were vegetarian non-students --> just says that # of \(vegetarian non-students\) equal to \(0.3x\) --> insufficeint, to calculate \(x\).

Re: data suffeciency [#permalink]
10 Nov 2010, 18:16

2

This post received KUDOS

Expert's post

mrinal2100 wrote:

Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger. No hamburger was eaten by any guest who was a student, a vegetarian, or both. If half of the guests were vegetarians, how many guests attended the party?

(1) The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians.

(2) 30% of the guests were vegetarian non-students.

can someone explain in detail

This is what I drew when I read the Question stem. Half of the guests were vegetarians so Total/2 stands for the complete vegetarian circle. All outside Vegetarian circle are Total/2.

Attachment:

Ques.jpg [ 17.29 KiB | Viewed 11856 times ]

Statement 1: Veg students : Veg non students = 2:3 Let me say they are 2x and 3x in number.

Non veg students : Non veg non-students = 4:3 (Since veg's ratio is half of non veg's ratio) Let me say they are 4y and 3y in number. So now my diagram looks like this:

Attachment:

Ques1.jpg [ 18.33 KiB | Viewed 11862 times ]

3y = 15 hence y = 5 Since 7y is half of the total, 35 is half of the total. So total number of students is 70. Sufficient.

Statement 2: We get that 30% of the guests were veg non students and we already know that 50% of the guests are veg so 20% of the guests are veg students. Essentially, we have got the 3:2 ratio of above. But we do not have the 4:3 ratio of above hence we cannot equate 15 to anything. Therefore, statement 2 is not sufficient alone. _________________

Re: Guests at a recent party ate a total of fifteen hamburgers. [#permalink]
27 Feb 2011, 18:24

Good one! Stumbled in the test. I like the MGMAT solution.

Non veg - Non Students is 15.

Since Nonveg Student to non student ratio is 4:3, therefore non veg students will be 20. 4/3=x/15 Therefore x= 20. That makes 35 NV and 35 Veg so total 70

Re: Guests at a recent party ate a totaal of [#permalink]
20 Oct 2012, 22:59

nitzz wrote:

Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger. No hamburger was eaten by any guest who was a student, a vegetarian, or both. If half of the guests were vegetarians, how many guests attended the party?

(1) The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians.

(2) 30% of the guests were vegetarian non-students.

St 1: Sufficient: Veg attended in 2:3 so the Non veg attended in ratio 4:3. We now from Question stem Non veg - Non student ate 15 burgers. therefore Non veg attended the party in 20:15 (4:3). Total no of Non Veg = 35 nos. And total guests = 2*35=70 (from Question Stem). St 2: Not sufficient: cant calculate other group of non-veg and only %age is provided.

Guests at a recent party ate a total of fifteen hamburgers.. [#permalink]
05 Sep 2013, 08:52

Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger; no other guests ate hamburgers. If half of the guests were vegetarians, how many guests attended the party?

(1) The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians.

(2) 30% of the guests were vegetarian non-students.

Can anyone please elaborate any method for solving the problem? Unable to find an easy approach.

Re: Guests at a recent party ate a total of fifteen hamburgers.. [#permalink]
05 Sep 2013, 08:55

Expert's post

sapto123 wrote:

Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger; no other guests ate hamburgers. If half of the guests were vegetarians, how many guests attended the party?

(1) The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians.

(2) 30% of the guests were vegetarian non-students.

Can anyone please elaborate any method for solving the problem? Unable to find an easy approach.

Merging similar topics. Please refer to the solutions above. _________________

Re: Guests at a recent party ate a total of fifteen hamburgers. [#permalink]
14 Sep 2014, 14:54

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Guests at a recent party ate a total of fifteen hamburgers. [#permalink]
01 Dec 2014, 04:54

Bunuel, could you explain this statement: " --> so, non-vegetarian non-students compose 3/7 of all non vegetarians." Don't see how you get there. Thanks!

Last edited by Krage17 on 01 Dec 2014, 06:34, edited 1 time in total.

Guests at a recent party ate a total of fifteen hamburgers. [#permalink]
01 Dec 2014, 05:14

Expert's post

Krage17 wrote:

Bunuel, could you explain this statement: " --> so, non-vegetarian non-students compose 3/7 of all non vegetarians." Don't see how you there. Thanks!

Since non-vegetarian students plus non-vegetarian non-students equals all non-vegetarians, then (non-vegetarian non-students/(total) = 3/(4 + 3) = 3/7.

Re: Guests at a recent party ate a total of fifteen hamburgers. [#permalink]
01 Dec 2014, 08:35

It is. Took me a while to grasp it.

Bunuel wrote:

Krage17 wrote:

Bunuel, could you explain this statement: " --> so, non-vegetarian non-students compose 3/7 of all non vegetarians." Don't see how you there. Thanks!

Since non-vegetarian students plus non-vegetarian non-students equals all non-vegetarians, then (non-vegetarian non-students/(total) = 3/(4 + 3) = 3/7.

Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger. No hamburger was eaten by any guest who was a vegetarian, a student, or both. If half of the guests were vegetarians, how many guests attended the party?

1. The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians. 2. 30% of the guests were vegetarian non-students.

Re: OVERLAPPING SETS [#permalink]
28 Jun 2015, 22:33

campus1995 wrote:

Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger. No hamburger was eaten by any guest who was a vegetarian, a student, or both. If half of the guests were vegetarians, how many guests attended the party?

1. The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians. 2. 30% of the guests were vegetarian non-students.

On September 6, 2015, I started my MBA journey at London Business School. I took some pictures on my way from the airport to school, and uploaded them on...

When I was growing up, I read a story about a piccolo player. A master orchestra conductor came to town and he decided to practice with the largest orchestra...

I’ll start off with a quote from another blog post I’ve written : “not all great communicators are great leaders, but all great leaders are great communicators.” Being...