Guests at a recent party ate a total of fifteen hamburgers. : DS Archive
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# Guests at a recent party ate a total of fifteen hamburgers.

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Guests at a recent party ate a total of fifteen hamburgers. [#permalink]

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02 Jun 2009, 05:46
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Guests at a recent party ate a total of fifteen hamburgers. Each guest who was neither a student nor a vegetarian ate exactly one hamburger. No hamburger was eaten by any guest who was a student, a vegetarian, or both. If half of the guests were vegetarians, how many guests attended the party?

(1) The vegetarians attended the party at a rate of 2 students to every 3 non-students, half the rate for non-vegetarians.

(2) 30% of the guests were vegetarian non-students.

Pls Help
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Senior Manager
Joined: 15 Jan 2008
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Re: Guests at a recent party [#permalink]

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03 Jun 2009, 23:36
total 15 hamburgers were eaten..
Non veg non students = 15.

Total veg = 0.5X ( where X is the total )

1. statement is sufficient.

veg students / veg non students = 2 / 3

non veg students / non veg non students = 4/3

=> non veg students = 4*5 = 20.

As veg are half, non veg are other half.. total guests are 40..

2.statement is insuffient.

veg ( student and non student ) = 0.5X ( x is total no oif guests)
veg ( non student) = 0.3X
hence veg ( students ) = 0.2X

from teh prob statement, nonveg non student = 15

also, non veg ( student + non student ) = 0.5 X

but no idea on nonveg (student) == ???

Hence Answer will be A IMO..

Whats the OA ?
Re: Guests at a recent party   [#permalink] 03 Jun 2009, 23:36
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