I got D as the answer.

From the stem : h > 1 i.e., h can be [2, infinity]

I use => to state "it imples that"

(1)Each prime factor is sqrt(h) => the primefactors start with 2,3,5 etc.

=> h can be 2 or 3. The smallest primefactor is 2 and if we prove 'greater than' relation with it, the remaining numbers automatically are proved as for the relationship. Then 2 > sqrt(2) or sqrt(3). But, h cannot be 4. However, h be it 2 or 3 is prime and thus answers the question.

(2)Here also, h can be 2 or 3.

The smallest primefactor is 2 and if we prove 'greater than' relation with it, the remaining numbers automatically are proved as for the relationship.

B'cos 2 > 2/2 or 3/2. But, h cannot be 4.

However, h be it 2 or 3 is prime and thus answers the question.

So, it is D.

afife76 wrote:

h is an integer greater than 1,is h a prime number?

1) each prime factor is greater than square root h

2) each prime factor is greater than h/2

Please explain.

_________________

Awaiting response,

Thnx & Rgds,

Chandra