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Had to guess on this one since time was running and I was

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Director
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Had to guess on this one since time was running and I was [#permalink] New post 11 Sep 2007, 19:19
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Had to guess on this one since time was running and I was wasting my time solving this.
Some easy steps?
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Director
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Re: PS - Tree increasing every year, [#permalink] New post 11 Sep 2007, 19:39
ashkrs wrote:
Had to guess on this one since time was running and I was wasting my time solving this.
Some easy steps?


Little bit tricky...You need to read the problem carefully.

Ok, my take:

Let the rate of increment is r.
Original height is 4.

At the end of 1st year, height will be (4+r)
....
....

At the end of 4th year, height will be (4+4r)
....
....

At the end of 6th year, height will be (4+6r)

According to the problem, at the end of 6th year height of the tree will be 1/5 taller than what it was at the end of 4th year....

That means,

Height at the end of 6th year = height at the end of 4the year + 1/5(height at the end of 4the year)

=> 4+6r = (4+4r) + 1/5(4+4r)
=> 2r = 4/5(1+r)
=> 10r = 4+4r
=> 6r = 4
=> r = 4/6
=> r = 2/3

- Brajesh
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Re: PS - Tree increasing every year, [#permalink] New post 11 Sep 2007, 20:15
ashkrs wrote:
Had to guess on this one since time was running and I was wasting my time solving this.
Some easy steps?


I had this same problem on my GMATPrep 1. Had to guess. I tried using the rate formula to solve this (which I could have), but the rate method made the setup unnessicarily complicated. So I had to move on and guess. Afterwards, I got it in a couple of min w/o tryin the rate formula... owell.


Heres the solution. Make the two years equal eachother in algebraic terms.

Since year 6 is 1/5 taller. Then it is greater than year four by 20%.
X is the growth rate. and then number next to X represents the years.
120/100(4+4x) = 4+6x ---> 6/5(4+4x)=4+6x

24/5+24x/5=4+6x ---> 24/5-20/5=30x/5-24x/5 ---> 4/5=6x/5

x=2/3.
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 [#permalink] New post 11 Sep 2007, 22:23
Fastest way is to just write down on the scratch pad the following:

Each year grow by x ft.

Start: 4ft
End of year 1: 4+x
End of year 2: 4+2x
End of year 3: 4+3x
End of year 4: 4+4x
End of year 5: 4+5x
End of year 6: 4+6x

1/5(4+4x) + 4+4x = 4+6x
x = 2/3
Director
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Re: PS - Tree increasing every year, [#permalink] New post 12 Sep 2007, 06:39
Thanks all . You made it sound easy.
I was still struggling with verbage.
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 [#permalink] New post 28 Nov 2007, 21:44
ywilfred wrote:
Fastest way is to just write down on the scratch pad the following:

Each year grow by x ft.

Start: 4ft
End of year 1: 4+x
End of year 2: 4+2x
End of year 3: 4+3x
End of year 4: 4+4x
End of year 5: 4+5x
End of year 6: 4+6x

1/5(4+4x) + 4+4x = 4+6x
x = 2/3


Thanks guys!!...I recently got it in my gmatprep test too. Had to guess on it and got it wrong. But now it's clear as a crystal! :-)
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 [#permalink] New post 29 Nov 2007, 19:32
ywilfred wrote:
Fastest way is to just write down on the scratch pad the following:

Each year grow by x ft.

Start: 4ft
End of year 1: 4+x
End of year 2: 4+2x
End of year 3: 4+3x
End of year 4: 4+4x
End of year 5: 4+5x
End of year 6: 4+6x

1/5(4+4x) + 4+4x = 4+6x
x = 2/3


I did it the same way. My only change is very minor, but time saving:

1/5 more is the same as 6/5 of... so i immediately wrote:
4 + 6xx = 6/5(4 + 4x)

kinda nit-picky, but applied to multiple problems throughout the test could save a lot of time.
  [#permalink] 29 Nov 2007, 19:32
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