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Hard Solutions /Mixture problem 600-700 level [#permalink]
 08 Nov 2010, 14:02
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Solution Y is 30 percent liquid X and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solutions Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new liquid solution is liquid X? a 30% b 33 1/3% c 37 1/2% d 40% e 50%
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Re: Hard Solutions /Mixture problem 600-700 level [#permalink]
08 Nov 2010, 14:16
At the beggining, you have 8KG of solution Y, i.e.
70% * 8KG = 5,6 KG of Water
30% * 8KG = 2,4 KG of X
2KG of water evaporate:
5,6KG - 2KG = 3,6KG of Water
2,4KG of X
2KG of liquid are added:
3,6KG + 2*0,70 = 5KG of Water
2,4KG + 2*0,30 = 3 KG of X
So you have 3KG of X in 8KG (3 + 5) solution.
Therefore X concentration is 3/8 = 37,5%
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Re: Hard Solutions /Mixture problem 600-700 level [#permalink]
09 Nov 2010, 00:01
Answer:CTook time to solve this one, the statement 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid was confusing to me. After thinking more deeply, it was clear to me that new 2 kg of solution Y will also be 30% liquid X and 70% water, and then I was able to get the answer. That was a bit tricky and nice question. Kudos +1 for posting the question 
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Re: Hard Solutions /Mixture problem 600-700 level [#permalink]
09 Nov 2010, 00:25
Initially you start with 8kg of solution which has 2.4kg of X and 5.6kg of water Post evaporation : 2.4kg of X and 3.6kg of water Now we add back 2kg of Y --> 1.4Kg water + 0.6Kg X So we have left 5Kg Water & 3Kg X Percentage concentration is (3/5)*100 or 37.5%
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Re: Hard Solutions /Mixture problem 600-700 level [#permalink]
09 Nov 2010, 00:43
shrouded1 wrote: Initially you start with 8kg of solution which has 2.4kg of X and 5.6kg of water
Post evaporation : 2.4kg of X and 3.6kg of water
Now we add back 2kg of Y --> 1.4Kg water + 0.6Kg X
So we have left 5Kg Water & 3Kg X
Percentage concentration is (3/5)*100 or 37.5% Yea, that's exactly how I solved but you know at first I was kinda adding 2 to 6 kg without considering liquid X and water's concentration within 2 kg being added.
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Re: Hard Solutions /Mixture problem 600-700 level [#permalink]
10 Dec 2011, 13:51
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Re: Hard Solutions /Mixture problem 600-700 level [#permalink]
11 Dec 2011, 23:43
Initially we have 8kg of solution which has 3/10 0f 8= 2.4kg of X and 7/10 of 8 = 5.6kg of water after evaporation : 2.4kg of X and 3.6kg of water
Now we added 2kg of solution Y --> 7/10 of 2=1.4Kg water + 3/10 0f 2 =0.6Kg X
So we have left 5Kg Water & 3Kg X
Percentage concentration is (3/5)*100 or 37.5%
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Re: Hard Solutions /Mixture problem 600-700 level
[#permalink]
11 Dec 2011, 23:43
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