Have 6 words, A, B, C, D, E, F (for example). How many : PS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 21 Jan 2017, 18:54

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Have 6 words, A, B, C, D, E, F (for example). How many

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Joined: 04 Dec 2005
Posts: 80
Followers: 1

Kudos [?]: 20 [0], given: 0

Have 6 words, A, B, C, D, E, F (for example). How many [#permalink]

### Show Tags

28 Jun 2006, 16:30
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Have 6 words, A, B, C, D, E, F (for example). How many combinations are possible such that A is not at position 1, B is not at position 2, and C is not position 4, how many possibilities.
Manager
Joined: 19 Apr 2006
Posts: 231
Followers: 1

Kudos [?]: 2 [0], given: 0

### Show Tags

28 Jun 2006, 17:43
number of total possibility = 6! = 6*5*4*3*2*1 = 720

ABDCEF
ABDCFE
ABECDF
ABECFD
ABFCDE
ABFCED

720-6 = 714...
CEO
Joined: 20 Nov 2005
Posts: 2911
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 24

Kudos [?]: 273 [0], given: 0

Re: PS - combinations [#permalink]

### Show Tags

28 Jun 2006, 19:02
withme wrote:
Have 6 words, A, B, C, D, E, F (for example). How many combinations are possible such that A is not at position 1, B is not at position 2, and C is not position 4, how many possibilities.

Total = 6!

When A is at pos1 = 5!
When B is at pos2 = 5!
When C is at pos4 = 5!

Result = 6!-3*5! = 720-360 = 360
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Manager
Joined: 19 Apr 2006
Posts: 231
Followers: 1

Kudos [?]: 2 [0], given: 0

Re: PS - combinations [#permalink]

### Show Tags

28 Jun 2006, 19:06
ps_dahiya wrote:
withme wrote:
Have 6 words, A, B, C, D, E, F (for example). How many combinations are possible such that A is not at position 1, B is not at position 2, and C is not position 4, how many possibilities.

Total = 6!

When A is at pos1 = 5!
When B is at pos2 = 5!
When C is at pos4 = 5!

Result = 6!-3*5! = 720-360 = 360

Thanks, I believe that I miss read the question. I thought the question was asking something else...
Re: PS - combinations   [#permalink] 28 Jun 2006, 19:06
Display posts from previous: Sort by

# Have 6 words, A, B, C, D, E, F (for example). How many

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.