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# having trouble factoring this equation

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having trouble factoring this equation [#permalink]

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29 Jul 2012, 09:10
(m^n)*(1-m^-1)=(m^n-1)*(m-1)

can anyone help me?
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Re: having trouble factoring this equation [#permalink]

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29 Jul 2012, 22:27
jmuduke08 wrote:
(m^n)*(1-m^-1)=(m^n-1)*(m-1)

can anyone help me?

$$(m^n)*(1 - m^{-1}) = (m^{n-1})*(m - 1)$$

$$(m^{n-1})*m(1 - m^{-1}) = (m^{n-1})*(m - 1)$$

$$(m^{n-1})*(m - 1) = (m^{n-1})*(m - 1)$$

So basically, the LHS is the same as the RHS
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Re: having trouble factoring this equation   [#permalink] 29 Jul 2012, 22:27
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# having trouble factoring this equation

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