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# Help needed urgently!!!!!

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Manager
Joined: 02 Jul 2007
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Help needed urgently!!!!! [#permalink]

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03 Jul 2008, 14:13
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi Math Gurus,

Can you please provide the solutions by solving the questions from GMAT prep in the attached sheets??

Thanks,
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gmatprep.doc [303 KiB]

GMATPREP.doc [294 KiB]

SVP
Joined: 30 Apr 2008
Posts: 1888
Location: Oklahoma City
Schools: Hard Knocks
Followers: 39

Kudos [?]: 518 [0], given: 32

Re: Help needed urgently!!!!! [#permalink]

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03 Jul 2008, 14:35
I have an answer for the first document. It's C.

Statement 1) Insufficient because we are asked to find an exact number and the only information we have is a ratio.

Statement 2) This tells us the maxium number of women on the sightseeing tour, but this doesn't tell us any information about the number of men, or the relationship of the number of men to the number of women. Insufficient.

Together.

We know the following:

Women : Children & Children : Men
5:2 & 5 : 11

From this we know that the number of children must be the LCM (Least Common Multiple) of 2 & 5, which is 10.

so if # of children is 10, and the ratio of Children to Men is 5:11, then $$\frac{5}{10} = \frac{11}{x}$$

x = 22 is the number of men. So together the two statements are sufficient.

SECOND QUESTION:

We first are told the ratio 1:3. OJ:Water in cans. Then we're cleverly told the can = 12 oz.

if one can = 12 oz and we need 1 can of OJ and 3 cans of Water that's a total of 4 cans * 12 oz = 48 oz made per can.

We need to figure out how many cans are needed to make 200 servings of 6 oz each.

We can take 48 oz (amount of OJ made per can of 12 ounce concentrate) divide by 6 oz = 8 servings of 6 oz per can.

Now take the number of servings desired (200) divided by the number of servings we can make per can of OJ (8)

200 / 8 = 25
_________________

------------------------------------
J Allen Morris
**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$. GMAT Club Premium Membership - big benefits and savings Director Joined: 14 Aug 2007 Posts: 733 Followers: 9 Kudos [?]: 153 [0], given: 0 Re: Help needed urgently!!!!! [#permalink] ### Show Tags 03 Jul 2008, 18:47 jallenmorris wrote: I have an answer for the first document. It's C. Statement 1) Insufficient because we are asked to find an exact number and the only information we have is a ratio. Statement 2) This tells us the maxium number of women on the sightseeing tour, but this doesn't tell us any information about the number of men, or the relationship of the number of men to the number of women. Insufficient. Together. We know the following: Women : Children & Children : Men 5:2 & 5 : 11 From this we know that the number of children must be the LCM (Least Common Multiple) of 2 & 5, which is 10. so if # of children is 10, and the ratio of Children to Men is 5:11, then $$\frac{5}{10} = \frac{11}{x}$$ x = 22 is the number of men. So together the two statements are sufficient. >>From this we know that the number of children must be the LCM (Least Common >>Multiple) of 2 & 5, which is 10. Are you sure about this? IMHO answer to question 1 should be E We don't know totoal number of people on tour SVP Joined: 30 Apr 2008 Posts: 1888 Location: Oklahoma City Schools: Hard Knocks Followers: 39 Kudos [?]: 518 [0], given: 32 Re: Help needed urgently!!!!! [#permalink] ### Show Tags 03 Jul 2008, 20:23 We do know (when trying to decide between C and E) that statement 2 says the number of women on the sightseeing tour is less than 30. This lets us know what the maximum number is. If the ratio of Women:Children is 5:2, and the number of women is less than 30, then we also know that the number of women must be a multiple of 5, or it wouldn't reduce down to a 5:2 ratio. As for why the LCM of 2 and 5 gives us the least number of children on the tour, here is my reasoning. We know that whatever the number of children on the tour is, with relation to the men, that number must reduce to 5, and that same number with relation to the women, must reduce to 2. We have to find the lowest number that can do both. That's 10. 10 is divisible by 5 so if the # of children was 10, in order for Children:Men to be 5:11, the number of men on the tour must be 22. In order for the women:children ratio to be 5:2, with the number of children being 10, that's 5*2, so 5 (on the women's side) * 5 = 25. We know the number of children cannot be greater than 10 because the next number that reduces to 5 and 2 is 20. If you reduce 20 to 2, that's by 10, so if women:children = 5:2 and children = 20, then Women = 50, and Statement 2 says "the number of women on the tour is less than 30" _________________ ------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

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Manager
Joined: 02 Jul 2007
Posts: 77
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Kudos [?]: 8 [0], given: 1

Re: Help needed urgently!!!!! [#permalink]

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06 Jul 2008, 05:30
Thanks a lot Jallenmorris for helping out. The method you used to solve the ratio problem was faster than mine. I really appreciate.

What about the others?? Please I need help Math Gurus???

Regards.
Re: Help needed urgently!!!!!   [#permalink] 06 Jul 2008, 05:30
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# Help needed urgently!!!!!

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