NEW HERE? LEARN MORE
closeclose
Last visit was: 24 Apr 2024, 18:39 It is currently 24 Apr 2024, 18:39
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

A manufacturer produced x percent more video cameras in 1994 than in

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
mrmikec
Manager
Manager
Joined: 17 Dec 2005
Posts: 91
Own Kudos [?]: 152 [83]
Given Kudos: 0
Send PM
A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   Updated on: 15 Sep 2014, 20:40
10
Kudos
73
Bookmarks
00:00
A
B
C
D
E

Difficulty:

45% (medium)

Question Stats:

70% (02:01) correct 30% (02:21) wrong based on 1515 sessions
Hide Show timer Statistics
A manufacturer produced x percent more video cameras in 1994 than in 1993 and y percent more in 1995 than in 1994. If the manufacturer produced 1,000 video cameras in 1993, how many video cameras did the manufacturer produce in 1995?

(1) xy = 20
(2) x + y + xy/100 = 9.2
ShowHide Answer
Official Answer
B

Originally posted by mrmikec on 16 Jun 2006, 22:35.
Last edited by Bunuel on 15 Sep 2014, 20:40, edited 3 times in total.
Edited the question.
Most Helpful Reply
User avatar
L
GyanOne
CEO
CEO
Joined: 24 Jul 2011
Status: World Rank #4 MBA Admissions Consultant
Posts: 3187
Own Kudos [?]: 1585 [14]
Given Kudos: 33
GMAT 1: 780 Q51 V48
GRE 1: Q170 V170
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   06 Nov 2011, 22:21
6
Kudos
8
Bookmarks
Expert Reply
The question has one critical word missing. Am assuming as follows:
A manufacturer produced x percent more video cameras in 1994 than in 1993 and y percent more in 1995 than in 1994. If he produced 1000 video cameras in 1993, how many did he produce in 1995?

Video cameras produced in 1995 = 1000 * (1+x/100) * (1+y/100)
= 1000 * (1 + x/100 + y/100 + xy/10000) cameras
= 1000 + 1000/100 (x + y + xy/100) cameras
= 1000 + 10 (x + y + xy/100) cameras

Using statement (1), we know xy but not know x and y separately. Insufficient.
Using statement (2), we know x + y + xy/100 and so can calculate the expression above. Sufficient.

(B) it is.
User avatar
B
walker
SVP
SVP
Joined: 17 Nov 2007
Posts: 2408
Own Kudos [?]: 10035 [5]
Given Kudos: 361
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40
Send PM
GMAT ToolKit User
Re: DS: video cameras [#permalink] New post   25 Jan 2008, 00:49
5
Kudos
Expert Reply
B

\(N=1000*\frac{(100+x)}{100}*\frac{(100+y)}{100}=10*(100+x+y+\frac{xy}{100})\)
General Discussion
User avatar
paddyboy
Senior Manager
Senior Manager
Joined: 06 May 2006
Posts: 388
Own Kudos [?]: 77 [1]
Given Kudos: 2
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   Updated on: 17 Jun 2006, 11:45
1
Kudos
B.

Take,
m = 2003 production
n = 2004 production
p = 2005 production

n = (100 + x)*m/100 -- 1
p = (100 + y)*n/100 -- 2

Substituting 1 in 2,
=> p = (100 + x)(100 + y)*m/(100*100)
=> p = (1 + x/100 + y/100 + xy/10000)*m
=> p = (100 + x + y + xy/100)*m/100

#1. xy = 20

Insufficient; as we get
p = (100 + x + y + 20/100)*m/100 => still have 2 unknowns

#2. x + y + xy/100 = 9.2

Sufficient; as we get
p = (100 + 9.2)*m/100 => no more unknowns

Originally posted by paddyboy on 16 Jun 2006, 23:54.
Last edited by paddyboy on 17 Jun 2006, 11:45, edited 2 times in total.
User avatar
mrmikec
Manager
Manager
Joined: 17 Dec 2005
Posts: 91
Own Kudos [?]: 152 [2]
Given Kudos: 0
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   17 Jun 2006, 11:41
2
Kudos
paddyboy wrote:
B.

Take,
m = 2003 production
n = 2004 production
p = 2005 production

n = (100 + x)*m/100
p = (100 + y)*n/100

=> p = (100 + x)(100 + y)*mn/(100*100)
=> p = (1 + x/100 + y/100 + xy/10000)*mn
=> p = (100 + x + y + xy/100)*mn/100

#1. Insufficient
#2. Sufficient


I got the following:

1993 = m
1994 = n
1995 = p

1994 = ((100+x)/100)m
1995 = ((100+y)/100)n

sub N

1995 = ((100+x)/100)((100+y)/100)m

= ((10000+100x+100y+xy)/10000)m

= ((1+x/100+y/100+xy/10000))m

C1. xy = 20
INSUFFICENT

C2. x+y+xy/100= 9.2
rewritten as

x/100+y/100+xy/10000 = 9.2(1/100)=9.2/100

Thus
subing condition2 into the underlined statement gets me

( 1+ 0.092)m = ??

What happens to m? We just assume its 100.
User avatar
superman
Senior Manager
Senior Manager
Joined: 18 Jun 2009
Posts: 285
Own Kudos [?]: 105 [4]
Given Kudos: 15
Location: San Francisco
Concentration: IT
Schools:Duke,Oxford,IMD,INSEAD
GPA: 3.79
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   17 Jul 2009, 16:01
4
Kudos
This is tricky but simple

Lets the number of increase in camera be m for 1993 to 1994

==> m = 1000 * x/100 = 10x

Lets the number of increase in camera be n for 1994 to 1995

==> n = (1000 + 10x) * y/100 = (100 + x) * y/10 = 10y + xy/10

Now the cameras in 1995 = 1000 + a + b = 1000 + 10x + 10y + xy/10 = 10(100+x+y+xy/100)

Now using stmt 2 we can solve the above equation hence Stmt 2 is sufficient and hence answer is B

Note from stmt 1 we wont know values of x and y
avatar
fozzzy
Director
Director
Joined: 29 Nov 2012
Posts: 580
Own Kudos [?]: 6041 [4]
Given Kudos: 543
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   14 Jul 2013, 03:05
3
Kudos
1
Bookmarks
1993
1000

1994
\(1000( 1+\frac{x}{100})\)


1995
\(1000(1+\frac{x}{100)}(1+\frac{y}{100})\)


solve for 1995 and take \(\frac{1}{100}\) common you will get statement 2 sufficient!
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 92900
Own Kudos [?]: 618819 [4]
Given Kudos: 81588
Send PM
CAT Tests Forum Quiz Mode
A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   12 Sep 2013, 01:36
4
Kudos
Expert Reply
Similar questions to practice:
https://gmatclub.com/forum/the-annual-re ... 89184.html
https://gmatclub.com/forum/between-1980- ... 45738.html
User avatar
B
PiyushK
Director
Director
Joined: 22 Mar 2013
Status:Everyone is a leader. Just stop listening to others.
Posts: 611
Own Kudos [?]: 4595 [1]
Given Kudos: 235
Location: India
GPA: 3.51
WE:Information Technology (Computer Software)
Send PM
Reviews Badge
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   15 Sep 2014, 07:03
1
Kudos
I got E because of typo made in the question.

Original question :: A manufacturer produced x percent more video cameras in 1994 than in 1993
Typo :: A manufacturer produced x percent ____ video cameras in 1994 than in 1993

Bunuel please edit the question stem, it must be "x percent more"
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 92900
Own Kudos [?]: 618819 [0]
Given Kudos: 81588
Send PM
CAT Tests Forum Quiz Mode
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   15 Sep 2014, 20:42
Expert Reply
PiyushK wrote:
I got E because of typo made in the question.

Original question :: A manufacturer produced x percent more video cameras in 1994 than in 1993
Typo :: A manufacturer produced x percent ____ video cameras in 1994 than in 1993

Bunuel please edit the question stem, it must be "x percent more"


Thank you! Edited the typo.
User avatar
G
keats
Director
Director
Joined: 28 Nov 2014
Posts: 754
Own Kudos [?]: 1263 [0]
Given Kudos: 86
Concentration: Strategy
Schools: Fisher '19 (M$)
GPA: 3.71
Send PM
Reviews Badge
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   07 Jun 2015, 04:42
93 –10^3
94 – 10^3(1+x/100)
95- 10^3(1+y/100)(1+x/100)

To calculate: 10^3 ( 1 + 1/10^2(x + y +xy/10^2))

Clearly B is sufficient
avatar
SonofAnarchy
Manager
Manager
Joined: 26 Apr 2015
Posts: 120
Own Kudos [?]: 10 [0]
Given Kudos: 134
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   08 Jun 2015, 23:17
superman wrote:
This is tricky but simple

Lets the number of increase in camera be m for 1993 to 1994

==> m = 1000 * x/100 = 10x

Lets the number of increase in camera be n for 1994 to 1995

==> n = (1000 + 10x) * y/100 = (100 + x) * y/10 = 10y + xy/10

Now the cameras in 1995 = 1000 + a + b = 1000 + 10x + 10y + xy/10 = 10(100+x+y+xy/100)

Now using stmt 2 we can solve the above equation hence Stmt 2 is sufficient and hence answer is B

Note from stmt 1 we wont know values of x and y



hey,
i have a query.
we substituted the value of "xy" in the equation and are left with two unknown variable x and y.
Cant we substitute the value x=20/y also in the equation and make it a single variable equation?
From that we can find the value of x and y separately.
User avatar
adiagr
Manager
Manager
Joined: 18 Jan 2010
Posts: 210
Own Kudos [?]: 997 [0]
Given Kudos: 9
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   13 Jun 2016, 22:37
mrmikec wrote:
A manufacturer produced x percent more video cameras in 1994 than in 1993 and y percent more in 1995 than in 1994. If the manufacturer produced 1,000 video cameras in 1993, how many video cameras did the manufacturer produce in 1995?

(1) xy = 20
(2) x + y + xy/100 = 9.2



1993: 1000

1994: 1000*( 1+\(\frac{x}{100}\))

1995: {1000*( 1+\(\frac{x}{100}\))} *( 1+\(\frac{y}{100}\))

value of xy alone would not serve our purpose.

B is sufficient.
User avatar
L
KarishmaB
Tutor
Joined: 16 Oct 2010
Posts: 14817
Own Kudos [?]: 64903 [1]
Given Kudos: 426
Location: Pune, India
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   13 Jun 2016, 22:48
1
Kudos
Expert Reply
SonofAnarchy wrote:
superman wrote:
This is tricky but simple

Lets the number of increase in camera be m for 1993 to 1994

==> m = 1000 * x/100 = 10x

Lets the number of increase in camera be n for 1994 to 1995

==> n = (1000 + 10x) * y/100 = (100 + x) * y/10 = 10y + xy/10

Now the cameras in 1995 = 1000 + a + b = 1000 + 10x + 10y + xy/10 = 10(100+x+y+xy/100)

Now using stmt 2 we can solve the above equation hence Stmt 2 is sufficient and hence answer is B

Note from stmt 1 we wont know values of x and y



hey,
i have a query.
we substituted the value of "xy" in the equation and are left with two unknown variable x and y.
Cant we substitute the value x=20/y also in the equation and make it a single variable equation?
From that we can find the value of x and y separately.


For anyone having the same query:

You have xy = 20

Number in 1995 = 1000 * (1 + x/100 + y/100 + xy/10000)

You can put x = 20/y and get:

Number in 1995 = 1000 * ( 1 + 20/100y + y/100 + 20/10000)

What next? We still have an unknown variable y. This is not an equation that will help you solve for y. You need to find the value of the highlighted expression. Also, even if this were an equation, it is likely to give you multiple values of y.

Another thing you can note is that xy = 20 means there are multiple values of x and y possible. e.g. x = 2, y = 10 or x = 4, y = 5 etc.
The value of the expression will change depending on which pair you take since x + y is different in each case.
User avatar
S
iliavko
Senior Manager
Senior Manager
Joined: 08 Dec 2015
Posts: 258
Own Kudos [?]: 117 [0]
Given Kudos: 36
GMAT 1: 600 Q44 V27
Send PM
Reviews Badge
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   07 Jan 2017, 17:15
How can this be done in 2 minutes?.. The factoring is super difficult. Is this a 600 Q?..
User avatar
L
KarishmaB
Tutor
Joined: 16 Oct 2010
Posts: 14817
Own Kudos [?]: 64903 [0]
Given Kudos: 426
Location: Pune, India
Send PM
A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   Updated on: 17 Oct 2022, 02:17
Expert Reply
iliavko wrote:
How can this be done in 2 minutes?.. The factoring is super difficult. Is this a 600 Q?..


You have to do no factorisation here. Just realise that it is a question involving successive percentage changes. You can calculate that using the formula
x + y + xy/100

Stmtn 2 gives you this value.

Stmnt 1 gives you xy = 20 only. In this case, x + y can take different values (1+20 or 2+10 or 4+5 etc). So the expression given above will have different values.

Originally posted by KarishmaB on 09 Jan 2017, 08:37.
Last edited by KarishmaB on 17 Oct 2022, 02:17, edited 1 time in total.
avatar
B
gmatassassin88
Manager
Manager
Joined: 22 Aug 2018
Posts: 51
Own Kudos [?]: 13 [0]
Given Kudos: 135
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   30 Mar 2020, 04:27
option B tells from 1993 to 1995 there is increment of 9.2% in production of cameras i.e 1000*9.2%, final production 1092.

However questions asks how many cameras produced in the year 1995 and not the final production VeritasKarishma

Kindly help
User avatar
G
ccooley
Manhattan Prep Instructor
Joined: 04 Dec 2015
Posts: 935
Own Kudos [?]: 1541 [1]
Given Kudos: 115
GMAT 1: 790 Q51 V49
GRE 1: Q170 V170
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   30 Mar 2020, 09:58
1
Kudos
Expert Reply
gmatassassin88 wrote:
option B tells from 1993 to 1995 there is increment of 9.2% in production of cameras i.e 1000*9.2%, final production 1092.

However questions asks how many cameras produced in the year 1995 and not the final production VeritasKarishma

Kindly help


The 1,092 number is the number produced in 1995. The statement tells you that the number produced in 1995 (in other words, (1+x/100)*(1+y/100)*1000) is 9.2% greater than the number produced in 1993. So, because you know the number produced in 1993, you can now find the number produced in 1995.

For instance, if you bake 10 cookies today, and you bake 40% more cookies tomorrow, the number of cookies you bake tomorrow is 14.
User avatar
L
KarishmaB
Tutor
Joined: 16 Oct 2010
Posts: 14817
Own Kudos [?]: 64903 [2]
Given Kudos: 426
Location: Pune, India
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   31 Mar 2020, 02:20
2
Kudos
Expert Reply
gmatassassin88 wrote:
option B tells from 1993 to 1995 there is increment of 9.2% in production of cameras i.e 1000*9.2%, final production 1092.

However questions asks how many cameras produced in the year 1995 and not the final production VeritasKarishma

Kindly help


Production per year is not a cumulative concept.
When we say "from 1993 to 1995, the production increased by 9.2%, it means if production in 1993 was 1000, production in 1995 is 1092.
This does not mean that in 1995, only 92 cameras were produced. It means in 1995, 1092 cameras were produced.
User avatar
bumpbot
Non-Human User
Joined: 09 Sep 2013
Posts: 32655
Own Kudos [?]: 821 [0]
Given Kudos: 0
Send PM
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink] New post   03 Jan 2024, 06:25
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
gmatclubot
Re: A manufacturer produced x percent more video cameras in 1994 than in [#permalink]
03 Jan 2024, 06:25
Moderator:
Bunuel
Math Expert
92900 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions