Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Here goes... Let's say you take the Quant section of the [#permalink]
14 Aug 2003, 07:59

Here goes...

Let's say you take the Quant section of the GMAT and get 33/37 correct. Now after the test is done, you find out that 5 of the 37 are "trial questions" that do not count. What are the chances that you got a perfect score on this section?

A cool problem. I have thought half an hour what to do.
You score perfect if all your wrong answers (4) are not counted (5).
In other words, for 5 noncounted units, 4 should be wrong plus one correct.

favorable outcomes: 4C4 (4 wrong answers)*33С1 (1 correct)
total 37C5

33/37C5=33*32!*5!/37!=1/17*7*3*37=1/13209

a sanity check: the smallest probability to score perfect is the case when 4 questions are not counted, we have 5, so the probability should be very small

When such a probability is any seizable? Let us imagine that 15 questions are not counted. Answering 33/37, we should have far more chances to score perfect. 4C4*33C11/37C15=0.02

A cool problem. I have thought half an hour what to do. You score perfect if all your wrong answers (4) are not counted (5). In other words, for 5 noncounted units, 4 should be wrong plus one correct.

favorable outcomes: 4C4 (4 wrong answers)*33С1 (1 correct) total 37C5

33/37C5=33*32!*5!/37!=1/17*7*3*37=1/13209

a sanity check: the smallest probability to score perfect is the case when 4 questions are not counted, we have 5, so the probability should be very small

When such a probability is any seizable? Let us imagine that 15 questions are not counted. Answering 33/37, we should have far more chances to score perfect. 4C4*33C11/37C15=0.02

comments?

This question is a little ambiguous. Your answer assumes that it is equally likely that you will miss an experimental question as a real one. But is that really true? I would think that the experimental question are somewhat more difficult, hence ETS needs to test them to determine whether they are fair, unambiguous, solvable, etc.... If the chance that you will miss an experimental question is significantly higher than a real one, it would raise the probability of increasing your score. However, since we have no data regarding the relative difficulty of real vs. experimental questions, I don't think you can calculate an answer. _________________

Best,

AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993

I felt the same ambiguity. Yet, I hope the approach is relevant, at least partly.

As I stated, your approach is exactly correct under the given assumption. However, bad assumption is almost always equal to bad result. _________________

Best,

AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993

As mentioned by AkamaiBrah, the difficulty level of the trial question will influence the outcome of answering a trial question right, in reality. Ignoring this fact for a moment,

We have 33 correct answers out of 37. 4 incorrect answers. 5 of those 37 questions are trial questions.

We can approach the problem in two ways, first (as stolyar approached),

33 correct answers, 4 wrong answers - choose 5 trial questions among them. Lets find out the probability of all 4 wrong answers being that of the trial questions.

p = (4 wrong being trial * one correct being trial )/ (choosing 5 trial from 37)
p = 4C4 * 33C1/37C5 = 1 *33/435893 = 1/13209

Second approach is,

32 real questions, 5 trial questions; find the probability of 4 wrong answers being that of the trial questions. [32 red balls, 5 blue balls - find the probability of 4 balls chosen being blue]

As mentioned by AkamaiBrah, the difficulty level of the trial question will influence the outcome of answering a trial question right, in reality. Ignoring this fact for a moment,

We have 33 correct answers out of 37. 4 incorrect answers. 5 of those 37 questions are trial questions.

We can approach the problem in two ways, first (as stolyar approached),

33 correct answers, 4 wrong answers - choose 5 trial questions among them. Lets find out the probability of all 4 wrong answers being that of the trial questions.

p = (4 wrong being trial * one correct being trial )/ (choosing 5 trial from 37) p = 4C4 * 33C1/37C5 = 1 *33/435893 = 1/13209

Second approach is,

32 real questions, 5 trial questions; find the probability of 4 wrong answers being that of the trial questions. [32 red balls, 5 blue balls - find the probability of 4 balls chosen being blue]

p = 5C4/37C4 = 5/66045 = 1/13209

Consider this simple approach:

He got four wrong. The chances of him getting any particular four questions wrong are the same so we can focus on just these four questions. He needs to match all four wrong answers with experimental questions, of which there are 5 in 37.

AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993

: Social ventures, both non-profits and for-profits, seek to better the world in such industries as education, microfinance, workforce development, public health and community development, among others. Organizations that...

Essay B for Stanford GSB will essentially ask you to explain why you’re doing what you’re doing. Namely, the essay wants to know, A) why you’re seeking...

Over the last week my Facebook wall has been flooded with most positive, almost euphoric emotions: “End of a fantastic school year”, “What a life-changing year it’s been”, “My...