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Here is an easy one to refresh your memory of Comb/Perm.

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VP
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Here is an easy one to refresh your memory of Comb/Perm.  [#permalink] New post 04 Feb 2006, 22:29
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Here is an easy one to refresh your memory of Comb/Perm.

Of a total of 10 teachers, 6 teach French, others teach Spanish and Chinese. If 3 teachers are to be selected for a committee including at least one French teacher, how many such committees are possible?
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VP
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 [#permalink] New post 04 Feb 2006, 22:36
116?

All combos - No French teacher
10C3 - 4C3 = 116
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 [#permalink] New post 04 Feb 2006, 23:48
F for French X for other

FXX + FFX + FFF

C(6,1)*C(4,2) + C(6,2)*C(4,1) + C(6,3)
36+60+20 = 116

easy but multiplication and addition will make it 1.30+ min question...
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 [#permalink] New post 06 Jun 2006, 17:38
GMATPREP says answer as 100.

Can someone explain.

thanks
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 [#permalink] New post 06 Jun 2006, 20:42
nshankaran wrote:
GMATPREP says answer as 100.

Can someone explain.

thanks

Maybe some typo in GMATPREP?
It should be 116 :wink:
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IE IMBA 2010

  [#permalink] 06 Jun 2006, 20:42
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Here is an easy one to refresh your memory of Comb/Perm.

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