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Here is another one that I had trouble with

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Manager
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Here is another one that I had trouble with [#permalink] New post 19 Aug 2006, 07:19
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Here is another one that I had trouble with.
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Manager
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 [#permalink] New post 19 Aug 2006, 07:21
Should I assume that there are no other types of animals on the farm other than pigs or cows?
Intern
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 [#permalink] New post 19 Aug 2006, 07:51
The stem tells you that there are 2/3 of 60 total animals that are either pigs or cows = 40 pigs or cows.

1) 2*C (> than) + P = 40 This by itself isn't enough.

2) P > 12, when combined with the first statement, p must be at least 13 which means C must be at least 27.

So 27+13 = 40, there are no other possibilities. So C is correct.
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 [#permalink] New post 22 Aug 2006, 05:29
The OA is C.

Thanks Mathec for contributing to this question :)

I had misread the question to mean that there are either 40 cows or 40 pigs :( grrr....

Cheers,
jjhko
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 [#permalink] New post 22 Aug 2006, 05:40
Tricky wording.

If statement 1 were to read: The farm has twice as many cows as pigs, then it would be sufficient.
  [#permalink] 22 Aug 2006, 05:40
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Here is another one that I had trouble with

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