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# Here is another one that I had trouble with

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Manager
Joined: 01 Apr 2006
Posts: 184
Followers: 1

Kudos [?]: 14 [0], given: 0

Here is another one that I had trouble with [#permalink]  19 Aug 2006, 07:19
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Difficulty:

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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Here is another one that I had trouble with.
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Manager
Joined: 01 Apr 2006
Posts: 184
Followers: 1

Kudos [?]: 14 [0], given: 0

Should I assume that there are no other types of animals on the farm other than pigs or cows?
Intern
Joined: 18 Aug 2006
Posts: 21
Followers: 0

Kudos [?]: 0 [0], given: 0

The stem tells you that there are 2/3 of 60 total animals that are either pigs or cows = 40 pigs or cows.

1) 2*C (> than) + P = 40 This by itself isn't enough.

2) P > 12, when combined with the first statement, p must be at least 13 which means C must be at least 27.

So 27+13 = 40, there are no other possibilities. So C is correct.
Manager
Joined: 01 Apr 2006
Posts: 184
Followers: 1

Kudos [?]: 14 [0], given: 0

The OA is C.

Thanks Mathec for contributing to this question

I had misread the question to mean that there are either 40 cows or 40 pigs grrr....

Cheers,
jjhko
Current Student
Joined: 29 Jan 2005
Posts: 5244
Followers: 23

Kudos [?]: 179 [0], given: 0

Tricky wording.

If statement 1 were to read: The farm has twice as many cows as pigs, then it would be sufficient.
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