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Here`s a strange one.... If y is a positive integer, is 3y

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Here`s a strange one.... If y is a positive integer, is 3y [#permalink] New post 22 Apr 2006, 22:30
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Here`s a strange one....

If y is a positive integer, is 3y odd?

1. y+319 is even
2. y cannot be evenly divided by any odd number other than 1.
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 [#permalink] New post 22 Apr 2006, 22:42
Answer is D!


1. y+319 = even, hence y is odd (odd + odd --> even). Thus 3y = oddxodd = odd!

2. Y is not an odd number. If it is odd, then Y should be divisible by 1 and by itself which is also odd!. But it says it is not divisble by any odd number, save 1. Thus it has to be even. Thus the 3x even = even!


Usually in GMAT both the options are congruent, ie they yield the same results. Here option 1 seems to indicate odd, while option 2 seems to indicate even! Thats kind of Weird for GMAT.

Where did you get this Q from? I have not seen this one in Kaplan though, which Kaplan is it?
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Re: WEIRD Kaplan DS [#permalink] New post 23 Apr 2006, 06:54
GMATT73 wrote:
Here`s a strange one....
If y is a positive integer, is 3y odd?
1. y+319 is even
2. y cannot be evenly divided by any odd number other than 1.

since y is a +ve integer,
from i, y is odd. so suff..
from ii, y is 1. also suff.

if y = 2, then 2 is evenly divided by 1 and 2. so only integer that is evenly (i guess evenly here doesnot mean 2, 4, 6 or so on) divided only by 1 is 1.

great question. D.
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Re: WEIRD Kaplan DS [#permalink] New post 23 Apr 2006, 20:12
Professor wrote:
GMATT73 wrote:
Here`s a strange one....
If y is a positive integer, is 3y odd?
1. y+319 is even
2. y cannot be evenly divided by any odd number other than 1.

since y is a +ve integer,
from i, y is odd. so suff..
from ii, y is 1. also suff.

if y = 2, then 2 is evenly divided by 1 and 2. so only integer that is evenly (i guess evenly here doesnot mean 2, 4, 6 or so on) divided only by 1 is 1.

great question. D.


Great explanation professor.
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 [#permalink] New post 23 Apr 2006, 20:58
Well, it says it cannot be evenly divided by any ODD integer other than 1. So it may well be divisible by 2.

A
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 [#permalink] New post 24 Apr 2006, 02:39
Maxi2006 wrote:
Well, it says it cannot be evenly divided by any ODD integer other than 1. So it may well be divisible by 2.

A


Be careful, evenly divided means divided without a remainder.

So the answer is 'D'.
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 [#permalink] New post 24 Apr 2006, 05:47
Here is the confusing part with the wording in statement 2.

---> y can either be 1 or an even number (2, 4, 8 ...) because they all divide evenly.

** If y = 1, then the answer to the stem is a definate YES.

<but>

** If y is an even number (also divisible by 1), then the answer to the stem is a definate NO.

Given these two possible conditions, how can both statements be sufficient (D) :?: :?: :?

BTW: This is from the "2005 Border`s Exclusive Edition" Kaplan prep text.

Last edited by GMATT73 on 24 Apr 2006, 06:22, edited 2 times in total.
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Re: WEIRD Kaplan DS [#permalink] New post 24 Apr 2006, 06:12
GMATT73 wrote:
Here`s a strange one....

If y is a positive integer, is 3y odd?

1. y+319 is even
2. y cannot be evenly divided by any odd number other than 1.


statement 2 means y is divisible by one and only one odd number that is 1.
--> y can be 1 and 2 ( 4, 8 and all exponents of 2)
--> 3y can be either odd or even
--> insuff

A it should be.
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 [#permalink] New post 24 Apr 2006, 06:17
D is the answer.

From 1st option > we get 3y is odd
from 2nd option > y is even and 3y is even so suff.
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 [#permalink] New post 24 Apr 2006, 06:20
but from statement 2, y can also be 1
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 [#permalink] New post 24 Apr 2006, 06:28
Thanks for backing me up here Laxie :-D Any other input guys?
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 [#permalink] New post 24 Apr 2006, 13:17
I agree. y=1 satisfies the second condition so we don't really know if 3y is odd or even for that one. In other word the answer should be A.
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 [#permalink] New post 24 Apr 2006, 13:35
yes the answer should be A

for B 1 and all other even numbers can satisfy the criteria ...
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 [#permalink] New post 24 Apr 2006, 18:09
3y is odd only if y is odd. So the question si asking if y is odd.

1) y+319 is even. 319 is odd. So y must be odd. Sufficient.

2) y is prime, which could be odd (any primes other than 2) or not odd(the prime number 2). Insufficient.

Ans A
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Re: WEIRD Kaplan DS [#permalink] New post 24 Apr 2006, 19:57
GMATT73 wrote:
Here`s a strange one....

If y is a positive integer, is 3y odd?

1. y+319 is even
2. y cannot be evenly divided by any odd number other than 1.


good question...what is the OA?
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 [#permalink] New post 24 Apr 2006, 21:44
I read ii to mean y is prime as well but since it does not exclude 2 than it is not suff so A
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 [#permalink] New post 25 Apr 2006, 20:41
The OA, according to Kaplan is (D). I am still not convinced...
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 [#permalink] New post 25 Apr 2006, 21:20
GMATT73 wrote:
The OA, according to Kaplan is (D). I am still not convinced...


But as we know, Kaplan is sometimes very erroneous :!:
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 [#permalink] New post 25 Apr 2006, 21:31
laxieqv wrote:
GMATT73 wrote:
The OA, according to Kaplan is (D). I am still not convinced...


But as we know, Kaplan is sometimes very erroneous :!:


buddy, our math experts has cleared the confusion and misconception that D is not correct.
it was indeed a great discussion.
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 [#permalink] New post 25 Apr 2006, 21:44
Professor wrote:
laxieqv wrote:
GMATT73 wrote:
The OA, according to Kaplan is (D). I am still not convinced...


But as we know, Kaplan is sometimes very erroneous :!:


buddy, our math experts has cleared the confusion and misconception that D is not correct.
it was indeed a great discussion.


buddy, this time, the merit goes to Matt as he pointed out the confusion and put forward a thorough consideration :)
If we stay alert like Matt, keeping an eye on any trickiness of GMAT, we'll certainly ace the maths section :)
  [#permalink] 25 Apr 2006, 21:44
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