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# Here's another one

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Senior Manager
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02 Dec 2006, 18:55
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Here's another one!
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Senior Manager
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02 Dec 2006, 21:55
C?

X5 = X4 / (X4 + 1)
=> X4 / 2 = X4 / (X4 + 1)
=> X4 = 1

X1 = 8
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03 Dec 2006, 06:45
Tennis, would you mind explaing please - I'm not getting anywhere with this one.

(OA is C)

Thanks
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03 Dec 2006, 07:05
st 1 is insuff
st2 is insuff

Combining 1 and 2 we get x4 and x5. once we know x4 using the formula given in st1 we can do reverse engineering to get x1 thus suff
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03 Dec 2006, 07:40
I'm not familiar with the notation - in statement 1) What does xi mean?
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03 Dec 2006, 08:11
anindyat wrote:
C?

X5 = X4 / (X4 + 1)
=> X4 / 2 = X4 / (X4 + 1)
=> X4 = 1

X1 = 8

OK, I'm with you up to X4 = 1

How did you get X1 = 8?
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03 Dec 2006, 08:23
Equating the both statements we get the value of x4 and we could proceed by
using statement 1 alone we get x3 value on substitution and similarly x2 and finally x1
x1=8
hence C is the correct option..

Last edited by Pzazz on 03 Dec 2006, 08:28, edited 1 time in total.
Senior Manager
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03 Dec 2006, 08:24
anindyat wrote:
C?

X5 = X4 / (X4 + 1)
=> X4 / 2 = X4 / (X4 + 1)
=> X4 = 1

X1 = 8

OK, I'm with you up to X4 = 1

How did you get X1 = 8?

X4 = X3/2
X3 = 2 = X2 / 2
X2 = 4 = X1 /2
X4 = 8
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03 Dec 2006, 09:13
AHHHHHHHHHHHHHHH GOT IT

I think I may leave this forum today - am thinking through treacle.

Part of problem was that I was reading 1) as:

Xi = (Xi - 1)/2 instead of Xi = X(i-1)/2

Thanks a lot!
03 Dec 2006, 09:13
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