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# Here's another one

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Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

Here's another one [#permalink]  02 Dec 2006, 18:55
Here's another one!
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GMATclubQ5.xls [51 KiB]

Senior Manager
Joined: 08 Jun 2006
Posts: 342
Location: Washington DC
Followers: 1

Kudos [?]: 23 [0], given: 0

C?

X5 = X4 / (X4 + 1)
=> X4 / 2 = X4 / (X4 + 1)
=> X4 = 1

X1 = 8
Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

Tennis, would you mind explaing please - I'm not getting anywhere with this one.

(OA is C)

Thanks
Director
Joined: 01 Oct 2006
Posts: 500
Followers: 1

Kudos [?]: 18 [0], given: 0

st 1 is insuff
st2 is insuff

Combining 1 and 2 we get x4 and x5. once we know x4 using the formula given in st1 we can do reverse engineering to get x1 thus suff
Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

I'm not familiar with the notation - in statement 1) What does xi mean?
Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

anindyat wrote:
C?

X5 = X4 / (X4 + 1)
=> X4 / 2 = X4 / (X4 + 1)
=> X4 = 1

X1 = 8

OK, I'm with you up to X4 = 1

How did you get X1 = 8?
Manager
Joined: 25 Nov 2006
Posts: 60
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Kudos [?]: 2 [0], given: 0

Equating the both statements we get the value of x4 and we could proceed by
using statement 1 alone we get x3 value on substitution and similarly x2 and finally x1
x1=8
hence C is the correct option..

Last edited by Pzazz on 03 Dec 2006, 08:28, edited 1 time in total.
Senior Manager
Joined: 08 Jun 2006
Posts: 342
Location: Washington DC
Followers: 1

Kudos [?]: 23 [0], given: 0

anindyat wrote:
C?

X5 = X4 / (X4 + 1)
=> X4 / 2 = X4 / (X4 + 1)
=> X4 = 1

X1 = 8

OK, I'm with you up to X4 = 1

How did you get X1 = 8?

X4 = X3/2
X3 = 2 = X2 / 2
X2 = 4 = X1 /2
X4 = 8
Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

AHHHHHHHHHHHHHHH GOT IT

I think I may leave this forum today - am thinking through treacle.

Part of problem was that I was reading 1) as:

Xi = (Xi - 1)/2 instead of Xi = X(i-1)/2

Thanks a lot!
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