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Hot tea at a temperature of 60˚ and cold water

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Hot tea at a temperature of 60˚ and cold water [#permalink]  15 Jul 2006, 00:27
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Hot tea at a temperature of 60˚ and cold water at a temperature of 10˚ are added to 50 mL of lemon juice at room temperature (25˚). The resulting mixture has a temperature of 40˚. How much hot tea was added?

(1) The tea and water were added in a 2:1 ratio.
(2) The mixture has a volume of 275 mL

Last edited by kevincan on 15 Jul 2006, 05:34, edited 1 time in total.
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A) the mixture will have 650/15=43,3 degrees temperature.
The equation is (X*43,3)/(X+50)+50*25/(X+50)=40 and we can find how many ml of the tea is added
B) We can find the temperature of the added mixture and from there the amount of tea
IMO D
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D

Stem: 60T+10W+50*25 = (T+W+50)*40

St1: T = 2W. We can solve two equations for T and W. We get T = 50ml and W = 25ml: SUFF

St2: T + W + 50 = 300 i.e T+W = 250. We can solve two equations for T and W. We get T = 199 and W = 51: SUFF

But generally we don't get different answers in GMAT. Is my solution correct or not???
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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ps_dahiya wrote:
D

Stem: 60T+10W+50*25 = (T+W+50)*40

St1: T = 2W. We can solve two equations for T and W. We get T = 50ml and W = 25ml: SUFF

St2: T + W + 50 = 300 i.e T+W = 250. We can solve two equations for T and W. We get T = 199 and W = 51: SUFF

But generally we don't get different answers in GMAT. Is my solution correct or not???

We both made a mistake; in (1), T=150 and W= 75, total volume is 275mL, not 300 as I orginally stated. Q has been corrected, thanks!

OA: D
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