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How about this one? |C|2C|C|||=C all the solutions,

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SVP
SVP
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Joined: 03 Feb 2003
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How about this one? |C|2C|C|||=C all the solutions, [#permalink] New post 19 Jun 2003, 00:15
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How about this one?
|C–|2C|C|||=C

all the solutions, please :smoke
Manager
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Joined: 03 Jun 2003
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Location: Uruguay
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 [#permalink] New post 19 Jun 2003, 11:48
I hope you don┬┤t get angry this time (if I fail)

My answer -1,0,1

8-)
SVP
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Kudos [?]: 44 [0], given: 0

 [#permalink] New post 19 Jun 2003, 21:32
My solution:

|C–|2C|C|||=C ---- thus C>=0, remember that

CASE # 1 the undermodul stuff is nonnegative
C–|2C|C||=C
|2C|C||=0
C=0 seems OK

CASE# 2 the undermodul stuff is negative
C–|2C|C||=–C
|2C|C||=2C square both parts
4C^2*C^2=4C^2
C=0, C=1, C=–1, which does not match to the initial condition

Therefore: C={0, 1}
  [#permalink] 19 Jun 2003, 21:32
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How about this one? |C|2C|C|||=C all the solutions,

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