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SVP
Joined: 03 Feb 2003
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Kudos [?]: 76 [0], given: 0

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|C–|2C|C|||=C

Manager
Joined: 03 Jun 2003
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I hope you don┬┤t get angry this time (if I fail)

SVP
Joined: 03 Feb 2003
Posts: 1608
Followers: 6

Kudos [?]: 76 [0], given: 0

My solution:

|C–|2C|C|||=C ---- thus C>=0, remember that

CASE # 1 the undermodul stuff is nonnegative
C–|2C|C||=C
|2C|C||=0
C=0 seems OK

CASE# 2 the undermodul stuff is negative
C–|2C|C||=–C
|2C|C||=2C square both parts
4C^2*C^2=4C^2
C=0, C=1, C=–1, which does not match to the initial condition

Therefore: C={0, 1}
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